0

ページに 3 つのボタンがあり、同じページでそのフォームを送信したいのですが、ボタンを押すと、対応するクエリが実行されます。しかし、スクリプトにはいくつかの問題があります。

<?php
$db = mysql_connect('localhost', 'root', '') or
die ('Unable to connect. Check your connection parameters.');
mysql_select_db('easy_excel', $db) or die(mysql_error($db));

if ($_POST['submit'] =='delete_aabb') 
{
$query ='DELETE FROM aabb';
mysql_query($query, $db) or die(mysql_error($db));
echo 'All Data from aabb Deleted succecfully!';
}
elseif ($_POST['submit'] =='delete_bbcc') {
$query ='DELETE FROM bbcc';
mysql_query($query, $db) or die(mysql_error($db));
echo 'All Data from bbcc Deleted succecfully!';
}
elseif ($_POST['submit'] =='show_bbcc') {
$query = 'SELECT
name
FROM  bbcc';
$result = mysql_query($query, $db) or die(mysql_error($db));

echo '<table border="1">';
while ($row = mysql_fetch_assoc($result)) {
echo '<tr>';
foreach ($row as $value) {
echo '<td>' . $value . '</td>';
}
echo '</tr>';
}
echo '</table>';
}
?>

<html>
<head>
<title>Say My Name</title>
</head>
<body>
<form action="#" method="post">
<table>
<tr>
<input type="submit" name="submit" value="delete_aabb" />
</tr>

<tr>
<input type="submit" name="submit" value="delete_bbcc" /></td>
</tr>

<tr>
<input type="submit" name="submit" value="show_bbcc" /></td>
</tr>

</table>
</form>
</body>
</html>

このスクリプトは実行されていません。私を助けてください。

4

1 に答える 1

0

非推奨のMySQLの代わりにMySQLiを使用することをお勧めします。そして、あなたは関数について言及していると思います。isset()

<html>
<head>
<title>Say My Name</title>
</head>
<body>

<?php

/* ESTABLISH CONNECTION USING MYSQLi */

$con=mysqli_connect("localhost","root","","easy_excel");

if(mysqli_connect_errno()){

echo "Error".mysqli_connect_error();
}

if (isset($_POST['delete_aabb'])) /* IF DELETE_AABB IS CLICKED */
{
mysqli_query($con,"DELETE FROM aabb");
echo 'All Data from aabb Deleted succecfully!';
}
else if (isset($_POST['delete_bbcc'])) { /* IF DELETE_BBCC IS CLICKED */
mysqli_query($con,"DELETE FROM bbcc");
echo 'All Data from bbcc Deleted succecfully!';
}
else if (isset($_POST['show_bbcc'])) { /* IF SHOW_BBCC IS CLICKED */
$result=mysqli_query($con,"SELECT name FROM bbcc");

echo '<table border="1">';
while ($row = mysqli_fetch_assoc($result)) {
echo '<tr>';
foreach ($row as $value) {
echo '<td>' . $value . '</td>';
}
echo '</tr>';
}
echo '</table>';
}
?>

<form action="" method="POST">
<table>
<tr>
<input type="submit" name="submit" value="delete_aabb" name="delete_aabb"/>
</tr>

<tr>
<input type="submit" name="submit" value="delete_bbcc" name="delete_bbcc"/></td>
</tr>

<tr>
<input type="submit" name="submit" value="show_bbcc" name="show_bbcc"/></td>
</tr>

</table>
</form>
</body>
</html>
于 2014-03-27T08:34:49.350 に答える