python-2.7 - Python配列内の単語をどのように置き換えますか?

Question

私はこのコードを持っています:

word = ["General William Shelton, said the system",
        "which will provide more precise positional data",
        "and that newer technology will provide more",
        "Commander of the Air Force Space Command",
        "objects and would become the most accurate metadata"]

交換したい：

Replace “the” with “THE”, “
Replace “William Shelton” with “AliBaba”
Replace “data” with “SAMSUNG”

出力は次のようになります。

 General AliBaba,said THE system which will provide more precise
 positional SAMSUNG and that newer technology will provide more
 Commander of the Air Force Space Command objects and would become the
 most accurate metadata

ありがとうございました！

私はこれを試しました：

rep_word = {"the":"THE", "William Shelton":"AliBaba", "system":"Samsung"}
replace = re.compile(r'\b(' + '|'.join(rep_word.keys()) + r')\b')
result = replace.sub(lambda x: rep_word[x.group()], word)
print result

しかし、私はこのエラーを受け取りました: TypeError: expected string or buffer

Answer 1

Pythonで構築された関数「reduce」を使用できると思います：

def change(prev, s):
     ret = s.replace("the", "THE")
     ret = ret.replace("William Shelton","AliBaba")
     ret = ret.replace("data", "SAMSUNG")
     return prev+' '+ret

reduce(change, word, '')

Answer 2

import re
word = ["General William Shelton, said the system",
        "which will provide more precise positional data",
        "and that newer technology will provide more",
        "Commander of the Air Force Space Command",
        "objects and would become the most accurate metadata"]
replacements = [("the", "THE"), ("William Shelton", "AliBaba"), ("data", "SAMSUNG")]
compiled = [(re.compile(r'\b%s\b' % re.escape(s)), d) for s, d in replacements]
replaced = [reduce(lambda s,(regex,res): regex.sub(lambda _: res, s), compiled, w) for w in word]
result = ' '.join(replaced)
result
'General AliBaba, said THE system which will provide more precise positional SAMSUNG and that newer technology will provide more Commander of THE Air Force Space Command objects and would become THE most accurate metadata'

Answer 3

xは文字列です。x .replace ("X","Y") を使用します。(X を Y に置き換えます)。