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基本的に、ExcelのCOUNTIF(Range,Criteria)に相当するSQLを知りたい

この出力が欲しい

CALL ID |  Name  | Phone Number | # of Occurrences    
  0001  | Name1  |  0000000000  |        2    
  0002  | Name2  |  1111111111  |        1    
  0003  | Name1  |  0000000000  |        2    
  0004  | Name3  |  2222222222  |        2    
  0005  | Name5  |  4444444444  |        1    
  0006  | Name4  |  3333333333  |        1    
  0007  | Name3  |  2222222222  |        2

この出力ではありません

CALL ID |  Name  | Phone Number | # of Occurrences    
  0001  | Name1  |  0000000000  |        2    
  0002  | Name2  |  1111111111  |        1    
  0004  | Name3  |  2222222222  |        2    
  0005  | Name5  |  4444444444  |        1    
  0006  | Name4  |  3333333333  |        1

これは簡略化された表です。これは私の複雑なテーブルで、これが 結果です

私が望んでいたのは、予定が2つになるのを避け、代わりにそれらを別々の行にリストして、予定が1つだけになるようにすることです

ここにクエリがあります

SELECT
a."Call ID" as "Call ID",
CONCAT(a.Campaign, '-', a."CONTACT ID") as IDENTIFIER,
REPLACE(a."Campaign",'CW-','') as "Campaign",
a."DNIS" as "DNIS",
a."CONTACT ID" as "CONTACT ID",
a."first_name" as "first_name",
a."last_name" as "last_name",
a."city" as "city",
a."street" as "street",
a."zip" as "zip",
a."state" as "state",
a."number2" as "number2",
a."number1" as "number1",
a."Customer ID - real" as "Customer ID - real",
COUNT(a."Call ID") as "Dial Attempts"
FROM  "Five9 Calls" a 
group by 
CONCAT(a.Campaign, '-', a."CONTACT ID"),
REPLACE(a."Campaign",'CW-',''),
a."CONTACT ID",
a."first_name",
a."last_name",
a."city",
a."street",
a."zip",
a."state",
a."number2",
a."number1"
4

3 に答える 3

0

データから収集できる各電話番号の出現回数が必要な場合は、次を使用します。

SELECT [PHONE NUMBER],COUNT(NAME) AS OCCUR
FROM YOURTABLE
GROUP BY [PHONE NUMBER]
于 2013-08-19T19:50:05.713 に答える