sql - 現在の価格とは異なる最終価格を見つける

Question

次のような SQL Server テーブルに販売トランザクションがあります。

ItemNumber, TrxDate, UnitPrice
ABC, 1/1/2013, 10.00
ABC, 2/1/2013, 10.00
ABC, 3/1/2013, 13.00
ABC, 4/1/2013, 14.00
ABC, 5/1/2013, 14.00
XYZ, 1/1/2013, 18.00
XYZ, 2/1/2013, 18.00
XYZ, 3/1/2013, 20.00
XYZ, 4/1/2013, 20.00
XYZ, 5/1/2013, 20.00

このような出力を生成するストアド プロシージャが必要です

ItemNumber, LastPrice, PriorPrice
ABC, 14.00, 13.00
XYZ, 20.00, 18.00

Answer 1

SQL Server 2005 以降を想定:

;WITH CTE AS
(
    SELECT  *,
            RN=ROW_NUMBER() OVER(PARTITION BY ItemNumber ORDER BY TrxDate DESC)
    FROM (  SELECT  ItemNumber,
                    MAX(TrxDate) TrxDate,
                    UnitPrice
            FROM YourTable
            GROUP BY ItemNumber,
                     UnitPrice) A
)
SELECT  ItemNumber,
        MIN(CASE WHEN RN = 1 THEN UnitPrice END) LastPrice,
        MIN(CASE WHEN RN = 2 THEN UnitPrice END) PriorPrice
FROM CTE
GROUP BY ItemNumber

Answer 2

lag()最初に関数を使用して、価格がいつ変化するかを調べることができます。

select ItemNumber,
       max(case when seqnum = 1 then Price end) as LastPrice,
       max(case when seqnum = 2 then Price end) as PriorPrice
from (select t.*, row_number() over (partition by ItemNumber order by TrxDate desc) as seqnum
      from (select t.*,
                   lag(Price) over (partition by ItemNumber order by TrxDate) as PrevPrice
            from t
           ) t
      where Price <> PrevPrice or PrevPrice is NULL
     ) t
group by ItemNumber;

ラグは、SQL Server 2012 以降でのみ使用できます。

がない場合はlag()、相関サブクエリを使用して同じことを行うことができます。

select ItemNumber,
       max(case when seqnum = 1 then Price end) as LastPrice,
       max(case when seqnum = 2 then Price end) as PriorPrice
from (select t.*, row_number() over (partition by ItemNumber order by TrxDate) as seqnum
      from (select t.*,
                   (select top 1 t2.Price
                    from t t2
                    where t.ItemNumber = t2.ItemNumber and
                          t.TrxDate > t2.TrxDate
                    order by t2.TrxDate desc
                   ) as PrevPrice
            from t
           ) t
      where Price <> PrevPrice or PrevPrice is NULL
     ) t
group by ItemNumber;