c# - 2つのパラメータを持つC#ラムダグループクエリ?

Question

ラムダを使用して、片側だけで曲がっている車の数と、両側で曲がっている車の数を取得する方法は?

    public class Car
    {
        public int Id { get; set; }
        public string Name { get; set; }

        public Car(int _Id, string _Name)
        {
            Id = _Id;
            Name = _Name;
        }
    }

    public class Turn
    {
        public int Id { get; set; }
        public string Name { get; set; }

        public Turn(int _Id, string _Name)
        {
            Id = _Id;
            Name = _Name;
        }
    }

    public class CarTurn
    {
        public int Id { get; set; }
        public Car Car { get; set; }
        public Turn Turn { get; set; }

        public CarTurn(int _Id, Car _Car, Turn _Turn)
        {
            Id = _Id;
            Car = _Car;
            Turn = _Turn;
        }
    }

.

Car car1 = new Car(1, "VW");
Car car2 = new Car(2, "Volvo");
Car car3 = new Car(3, "BMW");

Turn left = new Turn(1, "Left");
Turn right = new Turn(2, "Right");

CarTurn ct1 = new CarTurn(1, car1, left);
CarTurn ct2 = new CarTurn(2, car1, right);
CarTurn ct3 = new CarTurn(3, car2, right);
CarTurn ct4 = new CarTurn(4, car3, left);

List<CarTurn> data = new List<CarTurn>();
data.Add(ct1);
data.Add(ct2);
data.Add(ct3);
data.Add(ct4);

この場合、結果は次のようになります。

片面：2
両面：1

編集

var groups = data.GroupBy(x => x.Car.Id);
var bothSides = groups.Count(g=> g.Any(x=> x.Turn.Id == 1) && g.Any(x=> x.Turn.Id == 2));
var oneSide = groups.Count(g=> (g.Any(x=> x.Turn.Id == 1) && !g.Any(x=> x.Turn.Id == 2))
                            || (!g.Any(x=> x.Turn.Id == 1) && g.Any(x=> x.Turn.Id == 2)));

これは戻ってきます：

両側: 1
片側: 0