2

ユーザー アクションのログを日付スタンプ付きのテーブルに保存しています。

ユーザーがプロジェクトに入るたびに、そのプロジェクトを閲覧したことがログに記録され、日時がスタンプされます。

ユーザーが最後に参加した上位 20 件のプロジェクトを取得したいと考えています。

これは私がこれまでに持っているものです:

SELECT DISTINCT TOP (20) Users_Tran_ID
FROM App_UserLog
WHERE (Users_ID = 'ADMIN') AND (Users_Transaction LIKE 'Permit Viewed%')
ORDER BY App_UserLog.Users_LogDate DESC

問題は、UNIQUE Users_Tran_ID が必要なため、出力に Users_LogDate を含めたくないということです。

SELECT から Users_LogDate を削除すると、次のエラーが発生します。

ORDER BY items must appear in the select list if SELECT DISTINCT is specified.

これが私が得る基本的な選択と結果セットです。個別の Users_Tran_ID と TOP 20 のみが必要です。

ADMIN   Permit Viewed   B2011-0012  2013-08-29 17:35:04.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 17:29:09.000
ADMIN   Permit Viewed   B2006-0043  2013-08-29 17:29:05.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 17:28:49.000
ADMIN   Permit Viewed   B2008-0167  2013-08-29 17:17:13.000
ADMIN   Permit Viewed   B2006-0043  2013-08-29 17:17:08.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 17:16:55.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 17:16:45.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 17:16:38.000
ADMIN   Permit Viewed   B2007-0478  2013-08-29 17:16:32.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 11:39:59.000
ADMIN   Permit Viewed   B2007-0478  2013-08-29 11:22:05.000
ADMIN   Permit Viewed   B2007-0478  2013-08-29 11:22:03.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 10:23:17.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 10:21:58.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 10:20:41.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 10:20:37.000
ADMIN   Permit Viewed   B2007-0478  2013-08-29 10:18:01.000
ADMIN   Permit Viewed   B2007-0478  2013-08-29 10:17:58.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 10:17:54.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 10:01:50.000
ADMIN   Permit Viewed   B2011-0012  2013-08-29 10:01:48.000
ADMIN   Permit Viewed   B2007-0478  2013-08-29 09:56:32.000
ADMIN   Permit Viewed   B2007-0478  2013-08-29 09:53:31.000
ADMIN   Permit Viewed   B2007-0478  2013-08-29 09:53:27.000
ADMIN   Permit Viewed   ENG2012-0141    2013-08-15 12:51:09.000
ADMIN   Permit Viewed   ENG2012-0141    2013-08-15 12:51:07.000
ADMIN   Permit Viewed   BLD2012-0094    2013-08-13 12:01:39.000
ADMIN   Permit Viewed   ENG2013-0047    2013-08-05 10:40:34.000
ADMIN   Permit Viewed   ENG2013-0047    2013-08-05 10:40:28.000
ADMIN   Permit Viewed   ENG2013-0047    2013-08-05 10:40:24.000
ADMIN   Permit Viewed   ENG2013-0047    2013-08-05 10:40:21.000
ADMIN   Permit Viewed   ENG2013-0047    2013-08-05 10:40:13.000
ADMIN   Permit Viewed   ENG2013-0047    2013-08-05 10:40:09.000
ADMIN   Permit Viewed   ENG2013-0047    2013-08-05 10:40:07.000
ADMIN   Permit Viewed   ENG2012-0141    2013-08-05 10:37:55.000
ADMIN   Permit Viewed   ENG2012-0141    2013-08-05 10:37:50.000
ADMIN   Permit Viewed   ENG2012-0141    2013-08-05 10:37:46.000
ADMIN   Permit Viewed   ENG2012-0141    2013-08-05 10:37:40.000
ADMIN   Permit Viewed   ENG2012-0141    2013-08-05 10:37:33.000
ADMIN   Permit Viewed   ENG2012-0141    2013-08-05 10:37:31.000
ADMIN   Permit Viewed   BLD2012-0919    2013-08-05 10:27:21.000
ADMIN   Permit Viewed   BLD2012-0919    2013-08-05 10:27:17.000
ADMIN   Permit Viewed   ENG2012-0119    2013-08-05 10:26:51.000
ADMIN   Permit Viewed   ENG2012-0119    2013-08-05 10:26:48.000

これどうやってするの？

4

3 に答える 3

5

group byではなく使用したいdistinct：

SELECT TOP (20) Users_Tran_ID
FROM App_UserLog
WHERE (Users_ID = 'ADMIN') AND (Users_Transaction LIKE 'Permit Viewed%')
GROUP BY Users_Tran_ID
ORDER BY max(App_UserLog.Users_LogDate) DESC;

集計を使用すると、最新のログ日付で並べ替えるように指定できます。ほら、それはあなたが望むことをするはずです。

于 2013-08-30T00:55:43.960 に答える
2 
SELECT Users_ID, Users_Transaction, Users_Tran_ID
FROM (
    SELECT DISTINCT TOP (20) Users_ID, Users_Transaction, Users_Tran_ID, Users_LogDate
    FROM App_UserLog
    WHERE (Users_ID = 'ADMIN') AND (Users_Transaction LIKE 'Permit Viewed%')
    ORDER BY App_UserLog.Users_LogDate DESC
) as a
于 2013-08-29T23:59:21.043 に答える
1

あなたはこのようなものを探しています:

SELECT TOP 20 Users_ID, 
              Users_Transaction, 
              Users_Tran_ID 
         FROM ( SELECT Users_ID, 
                       Users_Transaction, 
                       Users_Tran_ID, 
                       max(Users_LogDate) as MaxUsers_LogDate
                  FROM App_UserLog
                 WHERE (Users_ID = 'ADMIN') AND 
                       (Users_Transaction LIKE 'Permit Viewed%')
              GROUP BY Users_ID, Users_Transaction, Users_Tran_ID
             ) AS TopTransactions
ORDER BY MaxUsers_LogDate DESC

SQLFIDDLEを参照してください

于 2013-08-30T02:32:19.787 に答える