magento-1.7 - 子の 1 つが在庫切れの場合、バンドル製品を非表示にします

Question

製品コレクションをフィルタリングして、子の 1 つが在庫切れのバンドル製品を含まないコレクションを返すにはどうすればよいですか。

Answer 1

代替回答

Mage::getSingleton('catalog/product_status')->addVisibleFilterToCollection($collection);
        Mage::getSingleton('catalog/product_visibility')->addVisibleInCatalogFilterToCollection($collection);
        $otherProductIds = $collection->getAllIds();

        //get only bundle
        $collection = Mage::getResourceModel('catalog/product_collection')
                                        ->addAttributeToFilter('type_id','bundle');
        Mage::getSingleton('catalog/product_status')->addVisibleFilterToCollection($collection);
        Mage::getSingleton('catalog/product_visibility')->addVisibleInCatalogFilterToCollection($collection);
        $bundleIds = $collection->getAllIds();


        //checking bundle associate product stock status
        $readAdapter = Mage::getSingleton('core/resource')->getConnection('core_read');

        $select = $readAdapter->select()
                    ->from(array('css'=> Mage::getSingleton('core/resource')->getTableName('cataloginventory/stock_status')),array())
                    ->join(
                        array('bs'=> Mage::getSingleton('core/resource')->getTableName('bundle/selection')),
                        'bs.product_id = css.product_id',
                        array('parent_product_id')
                    )
                    ->where('bs.parent_product_id IN (?)',$bundleIds)
                    ->where('css.stock_status = 0')
                    ->group('bs.parent_product_id');
        $excludeBundleIds = $readAdapter->fetchCol($select);//return outstock associated products parent ids

        $allIds =   array_merge($otherProductIds, array_diff($bundleIds,$excludeBundleIds));

        $collection = Mage::getResourceModel('catalog/product_collection')
                    ->addAttributeToFilter('entity_id',array( 'in' => $allIds))

                    ->addMinimalPrice()
                    ->addFinalPrice();

        return $collection

これが役立つことを願っています