以下は、指定した形式のファイルを読み取り、結果を People の List (または必要に応じて ArrayList) にプッシュする例です。これに基づいて、それがあなたの好みであれば、文字列のリストを作成できるはずですが、人々のリストが必要だと思いますか?
class Program
{
static void Main(string[] args)
{
string fn = @"c:\myfile.txt";
IList list = new ArrayList();
FileReader(fn, ref list);
for (int i = 0; i < list.Count; i++)
{
Console.WriteLine(list[i].ToString());
}
Console.ReadKey();
}
public static void FileReader(string filename, ref IList result)
{
using (StreamReader sr = new StreamReader(filename))
{
string firstName;
string lastName;
string marks;
IgnoreHeaderRows(sr);
while (!sr.EndOfStream)
{
firstName = sr.EndOfStream ? string.Empty : sr.ReadLine();
lastName = sr.EndOfStream ? string.Empty : sr.ReadLine();
marks = sr.EndOfStream ? string.Empty : sr.ReadLine();
result.Add(new Person(firstName, lastName, marks));
}
}
}
const int HeaderRows = 2;
public void IgnoreHeaderRows(StreamReader sr)
{
for(int i = 0; i<HeaderRows; i++)
{
if(!sr.EndOfStream) sr.ReadLine();
}
}
}
public class Person
{
string firstName;
string lastName;
int marks;
public Person(string firstName, string lastName, string marks)
{
this.firstName = firstName;
this.lastName = lastName;
if (!int.TryParse(marks, out this.marks))
{
throw new InvalidCastException(string.Format("Value '{0}' provided for marks is not convertible to type int.", marks));
}
}
public override string ToString()
{
return string.Format("{0} {1}: {2}", this.firstName, this.lastName, this.marks);
}
public override int GetHashCode()
{
return this.ToString().GetHashCode();
}
}