0

次の表を考えると

mysql> describe customers;
+-------------+-------------+------+-----+---------+----------------+
| Field       | Type        | Null | Key | Default | Extra          |
+-------------+-------------+------+-----+---------+----------------+
| customer_id | int(11)     | NO   | PRI | NULL    | auto_increment |
| login       | varchar(16) | NO   |     | NULL    |                |
| password    | varchar(40) | NO   |     | NULL    |                |
| name        | varchar(32) | NO   | UNI | NULL    |                |
| address     | varchar(64) | NO   |     | NULL    |                |
| contact     | varchar(32) | NO   |     | NULL    |                |
+-------------+-------------+------+-----+---------+----------------+
6 rows in set (0.02 sec)  

mysql> describe orders;
+-----------------+-------------+------+-----+-------------------+----------------+
| Field           | Type        | Null | Key | Default           | Extra          |
+-----------------+-------------+------+-----+-------------------+----------------+
| customer_id     | int(11)     | NO   | MUL | NULL              |                |
| order_id        | int(11)     | NO   | PRI | NULL              | auto_increment |
| order_timeStamp | timestamp   | NO   |     | CURRENT_TIMESTAMP |                |
| item            | varchar(16) | NO   |     | NULL              |                |
| price           | double      | NO   |     | NULL              |                |
+-----------------+-------------+------+-----+-------------------+----------------+
5 rows in set (0.04 sec)

パラメータ化されたクエリ (私のコードは customer_id を渡します) に一致する注文のすべての行と、customers テーブルからの顧客名を取得したいと考えています。

それ、どうやったら出来るの?

4

2 に答える 2

1

JOIN2 つのテーブルをWHERE検索し、クエリの最後の句に条件を入れます。

SELECT
  o.order_id,  
  o.order_timestamp,
  o.item,
  o.price,
  c.name,
  c.address,
  c.contact
FROM Orders AS o
INNER JOIN Customers AS c ON o.customer_id = c.customer_id
WHERE o.customer_id = ?
于 2013-09-04T08:03:48.437 に答える
0
select orders.*, customers.name
from orders, customers
where orders.customer_id=customers.customer_id
and customers.customer_id='MY_ID';
于 2013-09-04T08:05:47.610 に答える