投稿を読んだ後:パスワードなしでログイン
私は個人的な試みをしました：
AppController:
function beforeFilter(){
$this->Auth->loginError = "This message shows up when the wrong credentials are
used";
//$this->Auth->authError = "This error shows up with the user tries to access a part
of the website that is protected.";
//$this->Auth->authError = "";
$this->Auth->fields = array(
'username' => 'username',
'password' => null
);
ユーザーコントローラー、内部add()：
// Save new user
if ($this->User->save(array('username' => $this->request->data['User']['username'],
'password' => $this->Auth->password(null),
'name' => $this->request->data['User']['name'],
'surname' => $this->request->data['User']['surname'],
'chosenLayout' => $this->request->data['User']['chosenLayout'],
'dateCreated' => $this->request->data['User']['dateCreated'],
'dateModified' => $this->request->data['User']['dateModified'],
'role_id' =>$this->request->data['User']['role_id']
))) {
$this->Session->setFlash(__('message_success_user_added',
array($this->request->data['User']['username'])), 'default', array(), 'success');
$this->redirect(array('action' => 'index'));
}
else {
// Validation error
$this->Session->setFlash(__('message_fail_validation'), 'default', array(), 'fail');
}
次に、管理者として入力し、null またはランダムなパスワードでダミー ユーザーを作成しました。データベースの暗号化されたパスワードを確認すると、すべて同じ (ハッシュされた null 文字列) でした。これは、add()機能の変更が機能したことを意味します...
UsersController の内部login():
// Login User
public function login() {
// Check if the user is already logged in
if ($this->Session->check('Auth.User.id')){
// Redirect to login page
$this->redirect($this->Auth->loginRedirect);
}
else{
// If the user is not logged in
session_set_cookie_params(0);
// If the request is a POST request
if ($this->request->is('post')) {
//get credentials
$this->username = $this->request->data['User']['username'];
$this->password = $this->request->data['User']['password'];
$this->domain = $this->request->data['User']['domain'];
//debug($this->username);
debug($this->domain) ;
//Check if username exists in local DB
//debug($this->User->findByUsername( $this->username ));
if ($this->Auth->login(
array(
'username'=> $this->username,
'password'=> null)
)){
// debug($this->Auth->login(array(
// 'username'=> $this->username,
// 'password'=> null
// )));
// Successful login
// Get all the user information and store in Session
//debug($this->Auth);
$this->User->id = $this->Auth->user('id');
debug($this->User->id);
debug($this->User);
$this->User->contain(array('User', 'Role' => array('Ui', 'Action.name')));
$this->Session->write('User', $this->User->read());
$actions = array();
foreach ($this->Session->read('User.Role.Action') as $key => $value){
array_push($actions, $value['name']);
}
$this->Session->write('User.Role.Action', $actions);
debug($actions);
// Render different layout depending on user type
if($this->Session->read('User.Role.Ui.name') == Configure::read('usertype.msp')){
$this->Session->write('SessionValues.ui', Configure::read('usertype.msp'));
$this->Auth->loginRedirect = array('controller' => 'PortStats', 'action' =>
'index');
}
else if($this->Session->read('User.Role.Ui.name') ==
Configure::read('usertype.tsc')){
$this->Session->write('SessionValues.ui', Configure::read('usertype.tsc'));
$this->Auth->loginRedirect = array('controller' => 'PortStats', 'action' =>
'index');
}
else if($this->Session->read('User.Role.Ui.name') ==
Configure::read('usertype.superAdminUserType')){
$this->Auth->loginRedirect = array('controller' => 'Uis', 'action' => 'index');
}
// Redirect to main login page
$this->redirect($this->Auth->loginRedirect);
}
else {
// Failed login user
session_destroy();
$this->Session->setFlash(__('Login failed:
access not granted'), 'default', array(), 'fail');
}
}
}
}
次に、新しいユーザーでログインしようとしましたが、ログインに失敗したというメッセージが表示されました。つまり、 を$this->Auth->login返しますfalse。
それはそれと同じくらい簡単なはずですが、何かがうまくいかないのです。
その間、私のデバッグ トレース:
警告 (2): foreach() に無効な引数が指定されました [APP\Controller\UsersController.php、85 行目]