4

初心者の質問です。dtd ファイル (USPTO dtd) から Java コードを生成しています。DTD はルート要素を次のように指定します。

<!ELEMENT us-patent-grant (doc-page+ | (us-bibliographic-data-grant , abstract* , drawings? , description , us-sequence-list-doc? , us-megatable-doc?,table-external-doc* , us-chemistry* , us-math* ,us-claim-statement , claims))>

次のバインディング スキーマで xjc を実行すると

    <?xml version="1.0"?>
    <xml-java-binding-schema version="1.0ea2">
       <element name="us-patent-grant" type="class" root="true"></element>
    </xml-java-binding-schema>

次の Java オブジェクトが生成されているのがわかります

    @XmlAccessorType(XmlAccessType.FIELD)
    @XmlType(name = "", propOrder = {
        "docPageOrUsBibliographicDataGrantOrAbstractOrDrawingsOrDescriptionOrUsSequenceListDocOrUsMegatableDocOrTableExternalDocOrUsChemistryOrUsMathOrUsClaimStatementOrClaims"
    })
    @XmlRootElement(name = "us-patent-grant")
    public class UsPatentGrant {
       ....

    @XmlElements({
        @XmlElement(name = "doc-page", required = true, type = DocPage.class),
        @XmlElement(name = "us-bibliographic-data-grant", required = true, type = UsBibliographicDataGrant.class),
        @XmlElement(name = "abstract", required = true, type = Abstract.class),
        @XmlElement(name = "drawings", required = true, type = Drawings.class),
        @XmlElement(name = "description", required = true, type = Description.class),
        @XmlElement(name = "us-sequence-list-doc", required = true, type = UsSequenceListDoc.class),
        @XmlElement(name = "us-megatable-doc", required = true, type = UsMegatableDoc.class),
        @XmlElement(name = "table-external-doc", required = true, type = TableExternalDoc.class),
        @XmlElement(name = "us-chemistry", required = true, type = UsChemistry.class),
        @XmlElement(name = "us-math", required = true, type = UsMath.class),
        @XmlElement(name = "us-claim-statement", required = true, type = UsClaimStatement.class),
        @XmlElement(name = "claims", required = true, type = Claims.class)
    })
    protected List<Object> docPageOrUsBibliographicDataGrantOrAbstractOrDrawingsOrDescriptionOrUsSequenceListDocOrUsMegatableDocOrTableExternalDocOrUsChemistryOrUsMathOrUsClaimStatementOrClaims;

     .........

public List<Object> getDocPageOrUsBibliographicDataGrantOrAbstractOrDrawingsOrDescriptionOrUsSequenceListDocOrUsMegatableDocOrTableExternalDocOrUsChemistryOrUsMathOrUsClaimStatementOrClaims() {
    if (docPageOrUsBibliographicDataGrantOrAbstractOrDrawingsOrDescriptionOrUsSequenceListDocOrUsMegatableDocOrTableExternalDocOrUsChemistryOrUsMathOrUsClaimStatementOrClaims == null) {
        docPageOrUsBibliographicDataGrantOrAbstractOrDrawingsOrDescriptionOrUsSequenceListDocOrUsMegatableDocOrTableExternalDocOrUsChemistryOrUsMathOrUsClaimStatementOrClaims = new ArrayList<Object>();
    }
    return this.docPageOrUsBibliographicDataGrantOrAbstractOrDrawingsOrDescriptionOrUsSequenceListDocOrUsMegatableDocOrTableExternalDocOrUsChemistryOrUsMathOrUsClaimStatementOrClaims;
}

だから私の質問は、長いゲッターの名前を変更するにはどうすればよいですか

getDocPageOrUsBibliographicDataGrantOrAbstractOrDrawingsOrDescriptionOrUsSequenceListDocOrUsMegatableDocOrTableExternalDocOrUsChemistryOrUsMathOrUsClaimStatementOrClaims

バインディングスキーマで？

前もって感謝します。

4

2 に答える 2