hibernate - org.hibernate.hql.ast.QuerySyntaxException: Applicant is not mapping を解決する方法

Question

次のような休止状態の構成ファイルがあります

    en<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
        "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
        "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
    <session-factory>
        <property name="hibernate.connection.driver_class">org.postgresql.Driver</property>
        <property name="hibernate.connection.password">postgres</property>
        <property name="hibernate.connection.url">jdbc:postgresql://localhost:5432/mining</property>
        <property name="hibernate.connection.username">postgres</property>
        <property name="hibernate.dialect">org.hibernate.dialect.PostgreSQLDialect</property>
        <property name="hibernate.current_session_context_class">thread</property>
        <mapping resource="../WEB-INF/mams-hibern.xml"></mapping>
    </session-factory>
</hibernate-configuration>

mams-hibern.xml には、次のように構成されたマッピング ファイルが含まれています。

    <?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">

<beans>
<bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource"><ref bean="dataSource" /></property>
<property name="mappingResources">
<list>
<value>nic/mams/model/ApplicantHistory.hbm.xml</value>
<value>nic/mams/model/ApplicantAddressHistory.hbm.xml</value>
<value>nic/mams/model/ApplicantContactHistory.hbm.xml</value>
<value>nic/mams/model/ApplicantLeases.hbm.xml</value>
<value>nic/mams/model/GeneratedChallan.hbm.xml</value>
<value>nic/mams/model/OffenderType.hbm.xml</value>
<value>nic/mams/model/OffenceDetailRule.hbm.xml</value>
<value>nic/mams/model/TemperoryAppNotes.hbm.xml</value>
<value>nic/mams/model/TemperoryFilePath.hbm.xml</value>
<value>nic/mams/model/OtherDocuments.hbm.xml</value>
<value>nic/mams/model/OffenceSubactsRules.hbm.xml</value>
<value>nic/mams/model/OffenceActRules.hbm.xml</value>
<value>nic/mams/model/Vehicles.hbm.xml</value>
<value>nic/mams/model/ApprovedMajorMineral.hbm.xml</value>
<value>nic/mams/model/GoogleImage.hbm.xml</value>
<value>nic/mams/model/PasswordHistory.hbm.xml</value>
<value>nic/mams/model/LeaseTransfer.hbm.xml</value>
<value>nic/mams/model/TransferApplicantCompany.hbm.xml</value>
<value>nic/mams/model/MailSettings.hbm.xml</value>
<value>nic/mams/model/LeaseCompanyAddress.hbm.xml</value>
<value>nic/mams/model/FinancialYear.hbm.xml</value>
<value>nic/mams/model/IncomeTax.hbm.xml</value>
<value>nic/mams/model/AdditionalCharge.hbm.xml</value>
<value>nic/mams/model/MenuPrivileges.hbm.xml</value>
<value>nic/mams/model/AddressType.hbm.xml</value>
<value>nic/mams/model/AdvaloramRoyalty.hbm.xml</value>
<value>nic/mams/model/Agent.hbm.xml</value>
<value>nic/mams/model/AppJawsize.hbm.xml</value>
<value>nic/mams/model/Applicant.hbm.xml</value>
<value>nic/mams/model/ApplicantAddress.hbm.xml</value>
<value>nic/mams/model/ApplicantCompany.hbm.xml</value>
<value>nic/mams/model/ApplicantContact.hbm.xml</value>
<value>nic/mams/model/ApplicantLogin.hbm.xml</value>
<value>nic/mams/model/ApplicantStatus.hbm.xml</value>
<value>nic/mams/model/Application.hbm.xml</value>
<value>nic/mams/model/ApplicationDocument.hbm.xml</value>
<value>nic/mams/model/ApplicationHistory.hbm.xml</value>
<value>nic/mams/model/ApplicationMineral.hbm.xml</value>
<value>nic/mams/model/ApplicationSpecificQuery.hbm.xml</value>
<value>nic/mams/model/ApplicationSpecificQueryValues.hbm.xml</value>
<value>nic/mams/model/ApplicationStatus.hbm.xml</value>
<value>nic/mams/model/ApplicationSurvey.hbm.xml</value>
<value>nic/mams/model/ApplicationType.hbm.xml</value>
<value>nic/mams/model/ApplnSecurityFee.hbm.xml</value>
<value>nic/mams/model/AreaSpecification.hbm.xml</value>
<value>nic/mams/model/Bank.hbm.xml</value>
</property>
</beans>

しかし、私は例外を取得します

org.hibernate.hql.ast.QuerySyntaxException: Applicant がマップされていません d [Applicant から a を内部結合として選択 a.applications を b 内部結合 b.applicationType として c 内部結合 b.permits を d として d.permitNo=? および c.applicationTypeId=?]

これの解決策は何ですか.誰でも私を助けてください