ユーザーの文字入力に基づいて数字を追加しようとしています。ユーザーが 2 を入力した場合、変数 x に数値 2 を割り当てます。次に、ユーザーが 4 を入力した場合、変数 y に数値 4 が必要です。ユーザーが t を入力した場合、z に数値 10 を割り当てます。次に、2 + 4 + 10 を追加し、answer = 16 を出力します。何か提案はありますか? ありがとう!
#include<stdio.h>
int main(){
char a,b,c;
int numbers;
int answer;
int x,y,z;
printf("How many numbers would you like to add? (2-3): ");
scanf(" %d", &numbers);
printf("\nEnter value of your numbers. (2-9), T (for 10)\n");
scanf(" %c %c %c", &a, &b, &c);
if(numbers == 3){
if(a == "2"){
x = 2;
}
if(a == "3"){
x = 3;
}
if(a == "4"){
x = 4;
}
if(a == "5"){
x = 5;
}
if(a == "6"){
x = 6;
}
if(a == "7"){
x = 7;
}
if(a == "8"){
x = 8;
}
if(a == "9"){
x = 9;
}
if(a == "T" || a =="t"){
x = 10;
}
if(b == "2"){
y = 2;
}
if(b == "3"){
y = 3;
}
if(b == "4"){
y = 4;
}
if(b == "5"){
y = 5;
}
if(b == "6"){
y = 6;
}
if(b == "7"){
y = 7;
}
if(b == "8"){
y =8;
}
if(b == "9"){
y = 9;
}
if(b == "T" || b =="t"){
y = 10;
}
if(c == "2"){
z = 2;
}
if(c == "3"){
z = 3;
}
if(c == "4"){
z = 4;
}
if(c == "5"){
z = 5;
}
if(c == "6"){
z = 6;
}
if(c == "7"){
z = 7;
}
if(c == "8"){
z = 8;
}
if(c == "9"){
z = 9;
}
if(c == "T" || c =="t"){
z = 10;
}
printf("\nA = %c B = %c C = %c", a, b, c);
printf("\nx = %d y = %d z = %d", x, y, z);
answer = x + y + z;
printf("\nAnswer = %d\n", answer);
}
return 0;
}
そして私の出力は次のとおりです。
How many numbers would you like to add? (2-3): 3
Enter value of your numbers. (2-9), T (for 10)
2 4 T
A = 2 B = 4 C = T
x = 0 y = 4195472 z = 0
Answer = 4195472
次の警告も表示されます。
warning: comparison between pointer and integer