149

ViewPager間のスワイプに使用していますが、単純な XML レイアウト間のスワイプFragmentsに使用できますか?ViewPagerViews

Adapterこれは、フラグメント間をスワイプするために使用される ViewPager の私のページです。

import java.util.List;

import com.app.name.fragments.TipsFragment;

import android.support.v4.app.Fragment;
import android.support.v4.app.FragmentManager;
import android.support.v4.app.FragmentPagerAdapter;
import android.support.v4.app.FragmentTransaction;
import android.view.ViewGroup;

public class PageAdapter extends FragmentPagerAdapter {

    /**
     *
     */
    List<Fragment> fragments;
    public PageAdapter(FragmentManager fm,List<Fragment> frags) {
        super(fm);
        fragments = frags;

    }

    @Override
    public Fragment getItem(int arg0) {
        // TODO Auto-generated method stub
        return TipsFragment.newInstance(0, 0);
    }

    @Override
    public int getCount() {
        // TODO Auto-generated method stub
        return 4;
    }

    @Override
    public void destroyItem(ViewGroup container, int position, Object object) {
        FragmentManager manager = ((Fragment) object).getFragmentManager();
        FragmentTransaction trans = manager.beginTransaction();
        trans.remove((Fragment) object);
        trans.commit();

        super.destroyItem(container, position, object);
    }

}

そして、これは私のヒントの断片です:

public class TipsFragment extends Fragment
{
    public static TipsFragment newInstance(int image,int content)
    {
        TipsFragment fragment = new TipsFragment();
        return fragment;
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        View view = inflater.inflate(R.layout.tip_layout, null);
        return view;
    }
}

フラグメントではなくビューで動作するようにコードを変更するにはどうすればよいですか?

4

8 に答える 8

101

ではなく、これらの 2 つのメソッドをオーバーライドする必要がありますgetItem()

@Override
public Object instantiateItem(ViewGroup collection, int position) {
    View v = layoutInflater.inflate(...);
    ...
    collection.addView(v,0);
    return v;
}

@Override
public void destroyItem(ViewGroup collection, int position, Object view) {
    collection.removeView((View) view);
}
于 2013-09-10T04:16:50.180 に答える
72

この例を使用してください

子ビューをネストする単一の XML レイアウトを使用できます。

 <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:orientation="vertical">

        <android.support.v4.view.ViewPager
            android:id="@+id/pager"
            android:layout_width="match_parent"
            android:layout_height="match_parent">

            <LinearLayout
                android:id="@+id/page_one"
                android:layout_width="match_parent"
                android:layout_height="match_parent"
                android:orientation="vertical" >
                        <TextView
                        android:text="PAGE ONE IN"
                        android:layout_width="match_parent"
                        android:layout_height="match_parent"
                        android:textColor="#fff"
                        android:textSize="24dp"/>
            </LinearLayout>

            <LinearLayout
                android:id="@+id/page_two"
                android:layout_width="match_parent"
                android:layout_height="match_parent"
                android:orientation="vertical" >
                        <TextView
                        android:text="PAGE TWO IN"
                        android:layout_width="match_parent"
                        android:layout_height="match_parent"
                        android:textColor="#fff"
                        android:textSize="24dp"/>
            </LinearLayout>

    </android.support.v4.view.ViewPager>
</LinearLayout>

しかし...これもアダプターで処理する必要があります。ここでは、他のレイアウトをインフレートせずに、見つかったビュー ID を返します。

class WizardPagerAdapter extends PagerAdapter {

    public Object instantiateItem(ViewGroup collection, int position) {

        int resId = 0;
        switch (position) {
        case 0:
            resId = R.id.page_one;
            break;
        case 1:
            resId = R.id.page_two;
            break;
        }
        return findViewById(resId);
    }

    @Override
    public int getCount() {
        return 2;
    }

    @Override
    public boolean isViewFromObject(View arg0, Object arg1) {
        return arg0 == arg1;
    }

    @Override public void destroyItem(ViewGroup container, int position, Object object) {
        // No super
    }
}

// ViewPager アダプターを設定します

WizardPagerAdapter adapter = new WizardPagerAdapter();
ViewPager pager = (ViewPager) findViewById(R.id.pager);
pager.setAdapter(adapter);
于 2013-09-10T04:14:20.877 に答える
11

以前の回答に基づいて、適切かつ最も明確な方法でそれを達成するために次のクラスを作成しました(願っています):

public class MyViewPagerAdapter extends PagerAdapter {

    ArrayList<ViewGroup> views;
    LayoutInflater inflater;

    public MyViewPagerAdapter(ActionBarActivity ctx){
        inflater = LayoutInflater.from(ctx);
        //instantiate your views list
        views = new ArrayList<ViewGroup>(5);
    }

    /**
     * To be called by onStop
     * Clean the memory
     */
    public void release(){
     views.clear();
        views = null;
    }

    /**
     * Return the number of views available.
     */
    @Override
    public int getCount() {
        return 5;
    }

    /**
     * Create the page for the given position. The adapter is responsible
     * for adding the view to the container given here, although it only
     * must ensure this is done by the time it returns from
     * {@link #finishUpdate(ViewGroup)}.
     *
     * @param container The containing View in which the page will be shown.
     * @param position The page position to be instantiated.
     * @return Returns an Object representing the new page. This does not
     *         need to be a View, but can be some other container of
     *         the page.  ,container
     */
    public Object instantiateItem(ViewGroup container, int position) {
        ViewGroup currentView;
        Log.e("MyViewPagerAdapter", "instantiateItem for " + position);
        if(views.size()>position&&views.get(position) != null){
            Log.e("MyViewPagerAdapter",
                  "instantiateItem views.get(position) " +
                  views.get(position));
            currentView = views.get(position);
        }
        else{
            Log.e("MyViewPagerAdapter", "instantiateItem need to create the View");
            int rootLayout = R.layout.view_screen;
            currentView = (ViewGroup) inflater.inflate(rootLayout, container, false);

            ((TextView)currentView.findViewById(R.id.txvTitle)).setText("My Views " + position);
            ((TextView)currentView.findViewById(R.id.btnButton)).setText("Button");
            ((ImageView)currentView.findViewById(R.id.imvPicture)).setBackgroundColor(0xFF00FF00);
        }
        container.addView(currentView);
        return currentView;
    }

    /**
     * Remove a page for the given position. The adapter is responsible
     * for removing the view from its container, although it only must ensure
     * this is done by the time it returns from {@link #finishUpdate(ViewGroup)}.
     *
     * @param container The containing View from which the page will be removed.
     * @param position The page position to be removed.
     * @param object The same object that was returned by
     * {@link #instantiateItem(View, int)}.
     */
    @Override
    public void destroyItem(ViewGroup container, int position, Object object) {
        container.removeView((View)object);

    }

    /**
     * Determines whether a page View is associated with a specific key object
     * as returned by {@link #instantiateItem(ViewGroup, int)}. This method is
     * required for a PagerAdapter to function properly.
     *
     * @param view   Page View to check for association with <code>object</code>
     * @param object Object to check for association with <code>view</code>
     * @return true if <code>view</code> is associated with the key object <code>object</code>
     */
    @Override
    public boolean isViewFromObject(View view, Object object) {
        return view==((View)object);
    }
}

そして、アクティビティでそれを設定する必要があります:

public class ActivityWithViewsPaged extends ActionBarActivity {

    /**
     * The page Adapter: Manage the list of views (in fact here, its fragments)
     * And send them to the ViewPager
     */
    private MyViewPagerAdapter pagerAdapter;

    /**
     * The ViewPager is a ViewGroup that manage the swipe from left
     * to right to left.
     * Like a listView with a gesture listener...
     */
    private ViewPager viewPager;

    @Override
    protected void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_with_views);

        // Find the viewPager
        viewPager = (ViewPager) super.findViewById(R.id.viewpager);

        // Instantiate the PageAdapter
        pagerAdapter = new MyViewPagerAdapter(this);

        // Affectation de l'adapter au ViewPager
        viewPager.setAdapter(pagerAdapter);
        viewPager.setClipToPadding(false);
        viewPager.setPageMargin(12);

        // Add animation when the page are swiped
        // this instanciation only works with honeyComb and more
        // if you want it all version use AnimatorProxy of the nineoldAndroid lib
        //@see:http://stackoverflow.com/questions/15767729/backwards-compatible-pagetransformer
        if(Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB){
            viewPager.setPageTransformer(true, new PageTransformer());
        }
    }

    @Override
    protected void onStop() {
        super.onStop();
        pagerAdapter.release();
    }

XML ファイルが明らかな場所は、view_screen.xml です。

<xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
        android:id="@+id/screen"
        android:layout_width="match_parent"
        android:layout_height="match_parent">

 <TextView
        android:id="@+id/txvTitle"
        android:layout_width="wrap_content"
        android:layout_gravity="center"
        android:layout_height="wrap_content"
        android:layout_marginBottom="5dp"
        android:layout_marginTop="5dp"
        android:shadowColor="#FF00FF"
        android:shadowDx="10"
        android:shadowDy="10"
        android:shadowRadius="5"
        android:textSize="32dp"
        android:textStyle="italic"
        android:background="#FFFFF000"/>
    <LinearLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:background="#FFFF00F0">
        <TextView
            android:id="@+id/txvLeft"
            android:layout_width="wrap_content"
            android:layout_gravity="left"
            android:layout_height="wrap_content"
            android:layout_marginBottom="5dp"
            android:layout_marginTop="5dp"/>
        <TextView
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_weight="1"/>
        <TextView
            android:id="@+id/txvRight"
            android:layout_width="wrap_content"
            android:layout_gravity="right"
            android:layout_height="wrap_content"
            android:layout_marginBottom="5dp"
            android:layout_marginTop="5dp"/>
    </LinearLayout>
    <Button
        android:id="@+id/btnButton"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_gravity="center"/>
    <ImageView
        android:id="@+id/imvPicture"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:layout_gravity="center"/>
</LinearLayout>

また、ActivtyMain には次のレイアウトがあります。

<?xml version="1.0" encoding="utf-8"?>

<android.support.v4.view.ViewPager
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:paddingLeft="24dp"
    android:paddingRight="24dp"
    android:id="@+id/viewpager"
    android:background="#FF00F0F0">
</android.support.v4.view.ViewPager>

Brian と Nicholas の回答に大いに感謝します。最も明確な情報を追加し、この機能の優れた実践方法を強調したいと思います。

于 2015-05-22T09:59:39.580 に答える
4

@Nicholasの回答について詳しく説明したいと思います.IDでビューを取得するか、動的に追加されている場合は、その位置を指定してビューを直接取得できます

class WizardPagerAdapter extends PagerAdapter {

    public Object instantiateItem(View collection, int position) {

        View v = pager.getChildAt(position);

        return v;
    }

    @Override
    public int getCount() {
        return 3;
    }

    @Override
    public boolean isViewFromObject(View arg0, Object arg1) {
        return arg0 == ((View) arg1);
    }
}
于 2014-08-22T06:53:37.857 に答える