その意図は、ユーザーがプレイしたいかどうかを尋ね、オプションを出力し、ユーザー入力を受け取り、適切な面のサイコロを「転がす」ことをシミュレートすることです。結果を出力してから、別の選択肢を求めるなど。
プログラムの最初のサイクルは正常に動作しますが、もう一度再生するかどうかを尋ねる代わりに空白になります。サイコロを選択するために数字を入力すると、何を選択しても最初のサイコロの面数が出力されます。
#include <iostream>
#include <ctime>
using namespace std;
int throwDie(int Sides, int &throwResult)
{
throwResult = 1 + rand() % (Sides - 1 + 1);
return throwResult;
}
int main()
{
int dieTot = 0,
throwNumber = 0,
numberSides = 0,
throwResult = 0;
int die1 = 4;
int die2 = 6;
int die3 = 8;
int die4 = 10;
int die5 = 12;
int die6 = 20;
char rollAgain;
srand(unsigned(time(0) ));
START:
cout << "Do you want Play? ";
cin >> rollAgain;
cout << "How many sides? " << endl;
cout << "1 - 4 sided die\n";
cout << "2 - 6 sided die\n";
cout << "3 - 8 sided die\n";
cout << "4 - 10 sided die\n";
cout << "5 - 12 sided die\n";
cout << "6 - 20 sided die\n";
int choice;
cout << "Enter choice: ";
cin >> choice;
switch( choice ) {
case 1:
do {
cout << "You have choosen a 4 sided die? " << endl;
int numberSides = die1;
cout << numberSides << "-sided die rolled for a value of "
<< throwDie(numberSides, throwResult) << "!" << endl;
dieTot = dieTot + throwResult;
throwNumber++;
cin >> numberSides;
} while (choice != numberSides );
goto START;
break;
case 2:
do {
cout << "You have choosen a 6 sided die? " << endl;
int numberSides = die2;
cout << numberSides << "-sided die rolled for a value of "
<< throwDie(numberSides, throwResult) << "!" << endl;
dieTot = dieTot + throwResult;
throwNumber++;
cin >> numberSides;
cout << endl << "Total for " << throwNumber << " throws = " << dieTot << endl;
} while (choice != numberSides );
break;
case 3:
do {
cout << "You have choosen a 8 sided die? " << endl;
int numberSides = die3;
cout << numberSides << "-sided die rolled for a value of "
<< throwDie(numberSides, throwResult) << "!" << endl;
dieTot = dieTot + throwResult;
throwNumber++;
cin >> numberSides;
cout << endl << "Total for " << throwNumber << " throws = " << dieTot << endl;
} while (choice != numberSides );
break;
case 4:
do {
cout << "You have choosen a 10 sided die? " << endl;
int numberSides = die4;
cout << numberSides << "-sided die rolled for a value of "
<< throwDie(numberSides, throwResult) << "!" << endl;
dieTot = dieTot + throwResult;
throwNumber++;
cin >> numberSides;
cout << endl << "Total for " << throwNumber << " throws = " << dieTot << endl;
} while (choice != numberSides );
break;
case 5:
do {
cout << "You have choosen a 12 sided die? " << endl;
int numberSides = die5;
cout << numberSides << "-sided die rolled for a value of "
<< throwDie(numberSides, throwResult) << "!" << endl;
dieTot = dieTot + throwResult;
throwNumber++;
cin >> numberSides;
cout << endl << "Total for " << throwNumber << " throws = " << dieTot << endl;
} while (choice != numberSides );
break;
case 6:
do {
cout << "You have choosen a 20 sided die? " << endl;
int numberSides = die6;
cout << numberSides << "-sided die rolled for a value of "
<< throwDie(numberSides, throwResult) << "!" << endl;
dieTot = dieTot + throwResult;
throwNumber++;
cin >> numberSides;
cout << endl << "Total for " << throwNumber << " throws = " << dieTot << endl;
} while (choice != numberSides );
break;
default:
cout << "Not a proper entry.\n";
break;
cout << endl << "Total for " << throwNumber << " throws = " << dieTot << endl;
return 0;
}
}
各ケースステートメントの追加コードは次のとおりであると想定しています。
cout << numberSides << "-sided die rolled for a value of " << throwDie(numberSides, throwResult) << "!" << endl;
dieTot = dieTot + throwResult;
throwNumber++;
cin >> numberSides;
cout << endl << "Total for " << throwNumber << " throws = " << dieTot << endl;
}
while (choice != numberSides );
break;
それはコードの最後に行きますか?すべてのケースステートメントではありません。また、それを行う場合、while/do を関数に入れる必要さえありますか?