0

そのため、発効日に基づいて結果をランク付けできることを本当にうれしく思いますが、現在、あるデータ要素が繰り返され (POD)、別のデータ要素が EFFDT (DEPT) に基づいて変化するという問題が発生しています。

Pod の一意の値のみをランク付けしたいのですが、後で Dept をランク付けします。ただし、Pod は、より頻繁に変更される Dept に基づいています。以下のコードは私に与えます：

EENBR  PodRank POD DeptRank DeptNbr   DeptEffdt
100     1       73    1    12420      4/11/2005
100     2       73    2    12560      5/22/2005
100     3       73    3    12501      6/24/2007
200     1       12    1    50768      3/14/2005
200     2       13    2    10949      9/9/2012
300     1       73    1    12450      3/21/2005
300     2       73    2    12471      12/25/2005
300     3       73    3    12581      12/21/2008
300     4       73    4    12585      6/6/2010
300     5       73    5    12432      5/19/2013



SELECT DISTINCT 
       AL4.FULL_NAME,
       AL4.EMPLOYEE_NUMBER,
       dense_rank() over (partition by AL4.EMPLOYEE_NUMBER
                          order by AL3.EFFECTIVE_START_DATE) as POD_RANKING,
       AL7.POD_NBR as POD,
       row_number() over (partition by AL4.EMPLOYEE_NUMBER
                          order by AL3.EFFECTIVE_START_DATE) as DEPT_RANKING,
       AL3.RECORDVALUE AS DEPT_NUMBER,
       AL3.EFFECTIVE_START_DATE AS "DEPT EFFECTIVE DATE"     
  FROM T1 AL3,
       T2 AL4,
       T3 AL7 
 WHERE AL4.PERSON_ID = AL3.PERSON_ID
   AND AL4.EMPLOYEE_NUMBER = AL3.EMPLOYEE_NUMBER
   AND AL3.RECORDTYPE = 'DEPARTMENT_NUMBER'
   AND AL7.DEPT_NBR = AL3.RECORDVALUE
 Order By AL4.Employee_Number;

一意の値のみをランク付けする関数はありますか?

4

2 に答える 2

1

あなたが探している関数は分析関数dense_rank()です：

dense_rank() over (partition by eenbr order by pod) as ranking

これは、必要なものを取得する最も簡単な方法です。selectクエリの句に追加するだけです。

于 2013-09-18T18:36:43.827 に答える
0

There's no function for this, but you can get the result when you use nested window functions:

SELECT dt.*,
   SUM(flag) OVER (PARTITION BY EMPLOYEE_NUMBER
                   ORDER BY "DEPT EFFECTIVE DATE") AS POD_RANKING
FROM
 ( 
   SELECT
          AL4.FULL_NAME,
          AL4.EMPLOYEE_NUMBER,
          AL7.POD_NBR AS POD,
          ROW_NUMBER() OVER (PARTITION BY AL4.EMPLOYEE_NUMBER
                             ORDER BY AL3.EFFECTIVE_START_DATE) AS DEPT_RANKING,
          AL3.RECORDVALUE AS DEPT_NUMBER,
          AL3.EFFECTIVE_START_DATE AS "DEPT EFFECTIVE DATE",  
          CASE WHEN ROW_NUMBER() 
                    OVER (PARTITION BY AL4.EMPLOYEE_NUMBER,AL7.POD_NBR
                          ORDER BY AL3.EFFECTIVE_START_DATE) = 1 THEN 1 ELSE 0 END AS flag
     FROM T1 AL3,
          T2 AL4,
          T3 AL7 
    WHERE AL4.PERSON_ID = AL3.PERSON_ID
      AND AL4.EMPLOYEE_NUMBER = AL3.EMPLOYEE_NUMBER
      AND AL3.RECORDTYPE = 'DEPARTMENT_NUMBER'
      AND AL7.DEPT_NBR = AL3.RECORDVALUE
  ) dt
ORDER BY AL4.Employee_Number;

Edit: Ok, I noticed this is a overly complex version of a simple DENSE_RANK with different order, shortly before Gordon posted his answer :-) 

dense_rank() over (partition by AL4.EMPLOYEE_NUMBER order by AL7.POD_NBR)
于 2013-09-18T18:14:35.463 に答える