php - MySQL - 複数のクエリ

Question

次のSQLクエリがあります：-

    try {

        $query =   "SELECT VehicleSystemId, Fare FROM tblfixedfares
                    WHERE ShortPostCodeA IN ('$post_code_a','$post_code_a_two','$post_code_a_three','$post_code_a_four','$post_code_a_five')
                    AND ShortPostCodeB IN ('$post_code_b', '$post_code_b_two', '$post_code_b_three','$post_code_b_four','$post_code_b_five')
                    AND DayHalf = :day_half
                    AND VehicleSystemId IN ('Car', 'Est', 'Exec', 'ExecEst', '6B', '7B', '8B', 'Bus', '7W')";

        $stmt = $dbh->prepare($query);

        $stmt->bindParam(':day_half', self::$day_half, PDO::PARAM_STR);

        $stmt->execute();

        $result = $stmt->fetchAll(PDO::FETCH_ASSOC|PDO::FETCH_GROUP);
        //$result = $stmt->fetch(PDO::FETCH_COLUMN);
        $car = $result['Car'][0]['Fare'];
        $est = $result['Est'][0]['Fare'];
        $exec = $result['Exec'][0]['Fare'];
        $exec_est = $result['ExecEst'][0]['Fare'];
        $six_seater = $result['6B'][0]['Fare'];
        $seven_seater = $result['7B'][0]['Fare'];
        $eight_seater = $result['8B'][0]['Fare'];
        $bus = $result['Bus'][0]['Fare'];
        $wheelchair = $result['7W'][0]['Fare'];

        $stmt->closeCursor();

        $dbh = null;

        // Set fare to specific vehicle

        if ($_REQUEST['v_sys'] == NULL || $_REQUEST['v_sys'] == 'NULL' || $_REQUEST['v_sys'] == ''){
            $result = $car;
            return $result;
        }

        if ($_REQUEST['v_sys'] == 'Car') {
            $result = $car;
            return $result;
        }
        if ($_REQUEST['v_sys'] == 'Est') {
            $result = $est;
            return $result;
        }
        if ($_REQUEST['v_sys'] == 'Exec') {
            $result = $exec;
            return $result;
        }
        if ($_REQUEST['v_sys'] == 'ExecEst') {
            $result = $exec_est;
            return $result;
        }
        if ($_REQUEST['v_sys'] == '6B') {
            $result = $six_seater;
            return $result;
        }
        if ($_REQUEST['v_sys'] == '7B') {
            $result = $seven_seater;
            return $result;
        }
        if ($_REQUEST['v_sys'] == '8B') {
            $result = $eight_seater;
            return $result;
        }
        if ($_REQUEST['v_sys'] == 'Bus') {
            $result = $bus;
            return $result;
        }
        if ($_REQUEST['v_sys'] == '7W') {
            $result = $wheelchair;
            return $result;
        }

    }

基本的に、これを 5 つの異なるクエリに分割する必要があるため、最初に検索します。

query =   "SELECT VehicleSystemId, Fare FROM tblfixedfares
                WHERE ShortPostCodeA = '$post_code_a_five
                AND ShortPostCodeB = '$post_code_b_five
                AND DayHalf = :day_half
                AND VehicleSystemId IN ('Car', 'Est', 'Exec', 'ExecEst', '6B', '7B', '8B', 'Bus', '7W')";

一致が見つかった場合は結果を返し、それ以外の場合は次のクエリを試行します。

query =   "SELECT VehicleSystemId, Fare FROM tblfixedfares
                WHERE ShortPostCodeA = '$post_code_a_four
                AND ShortPostCodeB = '$post_code_b_four
                AND DayHalf = :day_half
                AND VehicleSystemId IN ('Car', 'Est', 'Exec', 'ExecEst', '6B', '7B', '8B', 'Bus', '7W')";

繰り返しますが、結果が見つからない場合は、次のクエリが試行されます:-

query =   "SELECT VehicleSystemId, Fare FROM tblfixedfares
                WHERE ShortPostCodeA = '$post_code_a_three
                AND ShortPostCodeB = '$post_code_b_three
                AND DayHalf = :day_half
                AND VehicleSystemId IN ('Car', 'Est', 'Exec', 'ExecEst', '6B', '7B', '8B', 'Bus', '7W')";

等々...

これを行う方法がわからないので、どんな助けでも大歓迎です。