ここで解決策が得られたことに本当に驚いています (私はこの種のプログラミングに慣れていないため)。
したがって、考慮すべき点が 2 つあります。検索に使用しているキーを把握し、エントリを追加および削除する必要があります。エントリを追加および削除するための共有サブシステム、またはクラスを使用して、これらのことを克服できると思います（それらについてはあまり知りません）。
誰かがそれを改善できるかもしれません。
私はしました、以下のセクションを見てください;-]
Dim myDict As New Dictionary(Of String, Double)
Dim myKeyDict As New Dictionary(Of String, String)
myDict.Add("key1", 5.5)
myKeyDict.Add("key2", "key1")
' Access Dictionary with key1
myDict("key1") = 7.7
Debug.Print(CStr(myDict("key1")))
' Acces Dictionary with key2
Dim thisKey1 As String = myKeyDict("key2") ' retrieve key1 with the help of key2
Debug.Print(CStr(myDict(thisKey1))) ' Acces the actuall dictionary with the retrieved key 1
そこで、key1 を文字列、key2 を文字列、val を double として、基本的な入力操作と出力操作を行う辞書のクラスを作成しました。
Public Class MultiKeyDictonaryDbl
Public DictVal As New Dictionary(Of String, Double) ' key1=Variablenname, val=Wert
Public DictKey1 As New Dictionary(Of String, String) ' key1=In/Output-Variablenname (Textdatei), key2=Variablenname
Public DictKey2 As New Dictionary(Of String, String) ' key2=In/Output-Variablenname (Textdatei), key1=Variablenname
Public length As Integer
Public Sub Add(key1 As String, key2 As String, val As Double)
DictVal.Add(key1, val)
DictKey1.Add(key1, key2)
DictKey2.Add(key2, key1)
End Sub
Public Sub Remove(key As String, id As Integer)
Dim key1 As String = Nothing
Dim key2 As String = Nothing
Dim chk As Boolean
If id = 1 Then
key1 = key
chk = DictKey1.TryGetValue(key1, key2)
ElseIf id = 2 Then
key2 = key
chk = DictKey2.TryGetValue(key2, key1)
End If
If chk = True Then
DictVal.Remove(key1)
DictKey1.Remove(key1)
DictKey2.Remove(key2)
End If
End Sub
Public Function getValue(key As String, id As Integer) As Double
Dim key1 As String = Nothing
Dim key2 As String = Nothing
Dim chk As Boolean
If id = 1 Then
key1 = key : chk = True
ElseIf id = 2 Then
key2 = key
chk = DictKey2.TryGetValue(key2, key1)
End If
If chk = True Then
chk = DictVal.TryGetValue(key1, getValue)
End If
If chk = False Then getValue = Double.PositiveInfinity
End Function
Public Function getList() As String(,)
Dim val As Double
Dim key1 As String = Nothing
Dim key2 As String = Nothing
Dim i As Integer = -1
' getLength in one line of code
length = -1 : Dim l1 As Integer = DictVal.Count : Dim l2 As Integer = DictKey1.Count : Dim l3 As Integer = DictKey2.Count : If l1 = l2 And l2 = l3 Then length = l1
If length < 1 Then Exit Function
Dim List(length - 1, 2) As String
For Each ele In DictKey2
i += 1
key2 = ele.Key : key1 = DictKey2(key2) : val = DictVal(key1)
List(i, 0) = key1 : List(i, 1) = key2 : List(i, 2) = CStr(val)
Next
getList = List
End Function
Public Function getLength() As Integer
getLength = -1
Dim l1 As Integer = DictVal.Count
Dim l2 As Integer = DictKey1.Count
Dim l3 As Integer = DictKey2.Count
If l1 = l2 And l2 = l3 Then getLength = l1
length = getLength
End Function
End Class
Sub testDictionaryVariablenVerarbeitung()
' some tests
Dim testit As New MultiKeyDictonaryDbl
testit.Add("Variablenname", "In/Output-Variablenname", 55.7)
testit.Add("Variablenname2", "In/Output-Variablenname2", 90.7)
Debug.Print(CStr(testit.getLength()))
testit.Add("Blub", "dabdi", 916)
testit.Remove("Variablenname", 1)
Dim liste(,) As String = testit.getList
Debug.Print(CStr(testit.getValue("Variablenname2", 1)))
Debug.Print(CStr(testit.getValue("dabdi", 2)))
Debug.Print(CStr(testit.getValue("dabdi", 1)))
End Sub