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キーと値のペアを含む 2 つの配列があります。

{
    "containerOne": [{
        "Id": 1,
            "Title": "TitleOne",
            "Responsibility": "ValueOne"
    }, {
        "Id": 2,
            "Title": "TitleTwo",
            "Responsibility": "ValueTwo"
    }]
}

{
    "containerTwo": [{
        "Id": 1,
            "Title": "TitleOne",
            "Responsibility": null
    }, {
        "Id": 2,
            "Title": "TitleTwo",
            "Responsibility": "null         
                               }
            ]
    }

両方の配列を比較し、各コンテナーのタイトルを比較したいと思います。タイトルが一致する場合、Responsibility の値を containerOne から containerTwo にコピーしたいと思います。ID が一致しないため、除外できます。タイトルのみが一貫します。

これを行う最も効率的な方法は何ですか?]

ありがとう

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編集

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配列をもう少し詳しく見てみると、返されるデータに微妙な違いがあります。

{
"AMLookupTasksList":
    [
        {
            "Id":1,
            "Title":"Create and Maintain an Onboarding Document",
            "Responsibility":"1. Onboarding|f101ccf1-c7d5-42e7-ba8f-48e88ac90a3d"
        },
        {
            "Id":2,
            "Title":"Execute Onboarding for New Consultants",
            "Responsibility":"1. Onboarding|f101ccf1-c7d5-42e7-ba8f-48e88ac90a3d"
        }
    ]

}

{
"AMTasksList":
    [
        {
            "Id":4,
            "Title":
                {
                    "$M_1":13,"$c_1":"Create and Maintain an Onboarding Document"
                },
            "Responsibility":null
        },
        {
            "Id":17,
            "Title":
                {
                    "$M_1":12,"$c_1":"Execute Onboarding for New Consultants"
                },
            "Responsibility":null
        }
    ]

}

2 番目の配列の Title 値を取得するための追加のループはありますか?

4

3 に答える 3

1

まず、から辞書を作成しますcontainerTwo。

var c2dict = {};
var c2i = containerTwo.innerContainer;
for (var i = 0; i < c2i.length; i++) {
    c2dict[c2i[i].Title] = c2i[i];
}

これを使用して、タイトルが一致したときにプロパティをコピーします。

var c1i = containerOne.innerContainer;
for (var i = 0; i < c1i.length; i++) {
    if (c2dict[c1i[i].Title]) {
        c2dict[c1i[i].Title].Property = c1i[i].Property;
    }
}
于 2013-09-19T19:51:16.740 に答える
1

これは少しやり過ぎかもしれませんが、シーケンスを無視して各オブジェクトを検索します。オブジェクトの構文を修正する必要がありましたが、それを含めます。オブジェクトに名前を付け、null 値の 1 つを引用符で囲みました。

var obj1 = {
    "containerOne": [{
        "Id": 1,
            "Title": "TitleOne",
            "Responsibility": "ValueOne"
    }, {
        "Id": 2,
            "Title": "TitleTwo",
            "Responsibility": "ValueTwo"
    }]
};
var obj2 = {
    "containerTwo": [{
        "Id": 1,
            "Title": "TitleOne",
            "Responsibility": null
    }, {
        "Id": 2,
            "Title": "TitleTwo",
            "Responsibility": null
    }]
};

今コード：

// lookup for first object:
var lookup = {};
// create referece to list above and use it everywhere
lookup.list = obj1;
for (var i = 0, len = lookup.list.containerOne.length; i < len; i++) {
    lookup[lookup.list.containerOne[i].Title] = lookup.list.containerOne[i];
}
// lookup for second object
var otherLookup = {};
otherLookup.list = obj2;
for (var i = 0, len = otherLookup.list.containerTwo.length; i < len; i++) {
    otherLookup[otherLookup.list.containerTwo[i].Title] = otherLookup.list.containerTwo[i];
}

// copy value for Responsibility from first to second on each matched in second.
var i = 0;
var len = lookup.list.containerOne.length;
for (i; i < len; i++) {
    // looks up value from second list in the first one and if found, copies 
    if (lookup[otherLookup.list.containerTwo[i].Title]) {
        otherLookup.list.containerTwo[i].Responsibility = lookup[otherLookup.list.containerTwo[i].Title].Responsibility;
    }
}

// alerts new value using lookup
alert(otherLookup["TitleOne"].Responsibility);

新しい構造の編集ですが、実際には同じ答えです:

var obj1 = {
    "AMLookupTasksList": [{
        "Id": 1,
            "Title": "Create and Maintain an Onboarding Document",
            "Responsibility": "1. Onboarding|f101ccf1-c7d5-42e7-ba8f-48e88ac90a3d"
    }, {
        "Id": 2,
            "Title": "Execute Onboarding for New Consultants",
            "Responsibility": "1. Onboarding|f101ccf1-c7d5-42e7-ba8f-48e88ac90a3d"
    }]
};
var obj2 = {
    "AMTasksList": [{
        "Id": 4,
            "Title": {
            "$M_1": 13,
                "$c_1": "Create and Maintain an Onboarding Document"
        },
            "Responsibility": null
    }, {
        "Id": 17,
            "Title": {
            "$M_1": 12,
                "$c_1": "Execute Onboarding for New Consultants"
        },
            "Responsibility": null
    }]
};

var lookup = {};
// create refernece to list above and use it everywhere
lookup.list = obj1;
for (var i = 0, len = lookup.list.AMLookupTasksList.length; i < len; i++) {
    lookup[lookup.list.AMLookupTasksList[i].Title] = lookup.list.AMLookupTasksList[i];
}
var otherLookup = {};
otherLookup.list = obj2;
for (var i = 0, len = otherLookup.list.AMTasksList.length; i < len; i++) {
    otherLookup[otherLookup.list.AMTasksList[i].Title.$c_1] = otherLookup.list.AMTasksList[i];
}

// copy value for Responsibility from first to second
var i = 0;
var len = otherLookup.list.AMTasksList.length;
for (i; i < len; i++) {
    if (lookup[otherLookup.list.AMTasksList[i].Title.$c_1]) {

        otherLookup.list.AMTasksList[i].Responsibility = lookup[otherLookup.list.AMTasksList[i].Title.$c_1].Responsibility;
    }
}

alert(otherLookup["Create and Maintain an Onboarding Document"].Responsibility);

2 番目の回答のフィドル: http://jsfiddle.net/n22V8/

于 2013-09-19T21:00:41.200 に答える