問題は、要素の頻度に従って配列をソートすることです。たとえば、入力配列が
{ 2, 3, 2, 4, 5, 12, 2, 3, 3, 3, 12 }
次に、配列を次のように変更します。
{ 3, 3, 3, 3, 2, 2, 2, 12, 12, 4, 5 }
このためのコードを書きましたが、正しく動作していますが、多くのスペースを使用しており、非常に複雑です。
このソリューションと、これに適用したロジックに満足していません。このコードを最適化したり、より良いロジックを提供したりできる人はいますか?
私のコードは次のとおりです。
#define _CRT_SECURE_NO_WARNINGS // this line to work code in visual studio
#include <stdio.h>
int main() {
/*
* n = number of integer
* i = loop variable
* j = inner loop variable
* c = number of distinct input
* buf = temprary storage for input value
* k = possibility of frequency of any no.
*/
int n, i, j, c = 0, buf, k;
int b; //act as flag
int arr[100] = { 0 };
int stack[200] = { 0 };
int top = -1;
printf("Enter the size of array(integer between 1-100):");
scanf("%d", &n);
n *= 2;
printf("----------Enter the elements in the array----------\n\n");
for (i = 0; i < n; i += 2) {
b = 0;
printf("Enter the element:");
scanf("%d", &buf);
for (j = 0; j <= i; j += 2) {
if (arr[j] == buf) {
arr[j + 1]++;
b = 1;
}
}
if (b == 0) {
c++;
arr[c * 2 - 2] = buf;
arr[c * 2 - 1]++;
}
}
for (i = 0; i < c * 2; i++)
printf("%d ", arr[i]);
//input done in form of (element,times of occurence i.e. frequency),to print array, write this outside of comment:
//for (i = 0; i < c * 2; i++) printf("%d ", arr[i]);
for (k = 1; k < n / 2; k++) { //checking for possible frequencies
for (j = c * 2 - 1; j > 0; j -= 2) {
//locations(index) to check in array for frequency
//left to right, so with same frequency no.,which occurred first will push in last.
if (arr[j] == k)
stack[++top] = j; //pushing(index of frequency) into stack in increasing order of frequency
}
}
//to print stack, write this outside of comment:
//printf("\nstack\n");
//for (i = top; i > -1; i--) printf("%d ",stack[i]);
//printing of elements in there decreasing order of frequency(pop from stack)
//we have to print element, number of times of its frequency
printf("\n\n----------Output array in sorted order of there frequency----------\n");
for (top; top > -1; top--) {
for (j = arr[stack[top]]; j > 0; j--)
printf("%d ", arr[stack[top] - 1]);
}
}