これは単純かもしれませんが、他のロジックを適用する必要があります:
WITH t(col) AS (
SELECT 1 FROM dual
UNION SELECT 2 FROM dual
UNION SELECT 3 FROM dual
UNION SELECT 4 FROM dual
UNION SELECT 5 FROM dual
)
SELECT col , --- will works as usual
(SELECT col FROM t WHERE col = outer_q.col) new_col, --working as well
(
SELECT sum (latest_col)
from
(
SELECT col latest_col FROM t WHERE col = outer_q.col
UNION ALL
SELECT col FROM t WHERE col = outer_q.col
)
)newest_col -- need to get an output "4"
from t outer_q where col = 2;
次のような単純な出力:
COL NEW_COL NEWEST_COL
---------- ---------- ----------
2 2 4
3番目の列に使用した内側に最も外側の値を使用する必要があります
EDITING -- より多くのデータを含むサンプル:
WITH
t(col) AS
( SELECT 1 FROM dual
UNION
SELECT 2 FROM dual
UNION
SELECT 3 FROM dual
UNION
SELECT 4 FROM dual
UNION
SELECT 5 FROM dual
),
t1(amount, col) AS
(SELECT 100 , 2 FROM dual
UNION
SELECT 200, 3 FROM dual
)
SELECT col,
(SELECT col FROM t WHERE col = outer_q.col
) new_col,
(SELECT SUM(x)
FROM
(SELECT col x FROM t
UNION ALL
SELECT amount x FROM t1
)
WHERE col = outer_q.col
) newest_col -- gives 315 as it takes whole `SUM`
FROM t outer_q
WHERE col = 2;
次のような出力が期待されます。
COL NEW_COL NEWEST_COL
---------- ---------- ----------
2 2 102
助けてくれてありがとう。