python - 負の数が入力されていない状態で数値を読み取るプログラムを作成してください。入力値の最大数を結果として出力

Question

私は次のように書いてみました：

print "Enter numbers, stops when negative value is entered:"
numbers = [input('value: ') for i in range(10)]
while numbers<0:

でも突然頭がおかしくなり、次に何をすればいいのかわからない

例は次のとおりです。

数値を入力し、負の値を入力すると停止します:

値: 5

値: 9

値: 2

値: 4

値: 8

値: -1

最大は 9 です

Answer 1

私はあなたがこのようなものが欲しいと思います:

# Show the startup message
print "Enter numbers, stops when negative value is entered:"

# This is the list of numbers
numbers = []

# Loop continuously
while True:
   
    try:
        # Get the input and make it an integer
        num = int(raw_input("value: "))
    
    # If a ValueError is raised, it means input wasn't a number
    except ValueError:

        # Jump back to the top of the loop
        continue

    # Check if the input is positive
    if num < 0:

        # If we have got here, it means input was bad (negative)
        # So, we break the loop
        break

    # If we have got here, it means input was good
    # So, we append it to the list
    numbers.append(num)

# Show the maximum number in the list
print "Maximum is", max(numbers)

デモ：

数値を入力し、負の値を入力すると停止します:

値: 5

値: 9

値: 2

値: 4

値: 8

値: -1

最大は 9 です

Answer 2

これらの行に沿って何かが欲しいようです：

def get_number():
    num = 0
    while True: # Loop until they enter a number
        try:
            # Get a string input from the user and try converting to an int
            num = int(raw_input('value: '))
            break
         except ValueError:
            # They gave us something that's not an integer - catch it and keep trying
            "That's not a number!"

     # Done looping, return our number
     return num

print "Enter numbers, stops when negative value is entered:"
nums = []
num = get_number() # Initial number - they have to enter at least one (for sanity)
while num >= 0: # While we get positive numbers
    # We start with the append so the negative number doesn't end up in the list
    nums.append(num)
    num = get_number()

print "Max is: {}".format(max(nums))