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年で区別される計算された属性を含むクエリを作成しようとしています。2007 年から現在の年まで。私のSQLがどのように見えるかの簡単な例：

SELECT users.id as id
       users.name as name
       SUM(CASE WHEN posts.approved = 1) AND posts.created_at BETWEEN '2007-01-01 00:00:00 +0100' AND '2007-12-31 23:59:59 +0100' THEN posts.ratings ELSE 0 END) as approved_rating_2007
       SUM(CASE WHEN posts.approved = 0) AND posts.created_at BETWEEN '2007-01-01 00:00:00 +0100' AND '2007-12-31 23:59:59 +0100' THEN posts.ratings ELSE 0 END) as rejected_rating_2007
       SUM(CASE WHEN posts.approved = 1) AND posts.created_at BETWEEN '2008-01-01 00:00:00 +0100' AND '2008-12-31 23:59:59 +0100' THEN posts.ratings ELSE 0 END) as approved_rating_2008
       SUM(CASE WHEN posts.approved = 0) AND posts.created_at BETWEEN '2008-01-01 00:00:00 +0100' AND '2008-12-31 23:59:59 +0100' THEN posts.ratings ELSE 0 END) as rejected_rating_2008
       etc...
FROM users
LEFT OUTER JOIN posts ON posts.user_id = users.id

2007 年から current_year までのレコードを常に含む何らかのループでそれを記述する方法はありますか?

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SELECT u.id,
      u.name,
      year(p.created_at) as create_year
      SUM(CASE WHEN p.approved = 1 then p.ratings else 0 end) as approved_rating,
      SUM(CASE WHEN p.approved = 0 then p.ratings else 0 end) as rejected_rating
FROM users u
LEFT OUTER JOIN posts p ON p.user_id = u.id
group by u.id, u.name, create_year
于 2013-10-09T12:34:38.383 に答える