python - Python のタプルのすべての項目

Question

整数のいくつかのタプルといくつかの整数で構成されるタプルがあります.今、((1, 2), 3, (4, 5), 6)そこからすべての整数が必要です。私が書いた：

def get_all_items(iterable):
    t = []

    for each in iterable:
        if type(each) == int:
            t.append(each)
        else:
            t.extend(each)

    return tuple(t)

わたしにはできる。これを行うより良い方法はありますか？

Answer 1

チートの方法を忘れないでください

>>> from ast import literal_eval
>>> t = ((1, 2), 3, (4, 5), 6)
>>> literal_eval(repr(t).translate(None, '()'))
(1, 2, 3, 4, 5, 6)

Answer 2

I think your way is fine. Here's another way, using recursion, which will work for an arbitrarily-deeply-nested iterable structure:

def get_all_items(iterable):
    try:
        result = []
        for element in iterable:
            result += detuple(element)
        return result
    except TypeError:
        return [iterable]

Also, it may be useful to know that the operation you're describing is known as "flattening" a data structure.

Answer 3

このようにコードを単純化できます

def get_all_items(iterable):
    t = []
    for each in iterable:
        t.extend(list(each) if isinstance(each, tuple) else [each])
    return tuple(t)

print get_all_items(((1, 2), 3, (4, 5), 6))

出力

(1, 2, 3, 4, 5, 6)

Answer 4

from itertools import chain

def flatten(items):
  def renest():
    for item in items:
      try:
        yield iter(item)
      except TypeError:
        yield iter([item])
  return list(chain.from_iterable(renest()))

Answer 5

import itertools
itertools.chain.from_iterable(
    item if hasattr(item, '__iter__') else (item,)
        for item in iterable 
)