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私は C++ Mind Reader プログラムを作成していますが、これはほぼ完成しています。ただし、2 番目の cin をスキップする必要があると感じています。私は検索しましたが、何が間違っているのか正確にはわかりません。私はコードを調べましたが、何かばかげたことをしたに違いありませんが、まだ困惑しています。スキップされた cin は 32 行目にあり、これが私のコードです。

#include <iostream>
#include <string>
#include <cstdlib>

using namespace std;

int main()
{
    //declaring variables to be used later
    string name;
    string country;
    int age;

    //header goes below
    cout << "                     @@@@@@@@@@@@-MIND READER-@@@@@@@@@@@@\n\n";

    //asks if the user would like to continue and in not, terminates
    cout << "Would like you to have your mind read? Enter y for yes and n for no." << endl;
    cout << "If you do not choose to proceed, this program will terminate." << endl;
    string exitOrNot;
    //receives user's input
    cin >> exitOrNot;
    //deals with input if it is 'y'
    if (exitOrNot == "y"){
        cout << "Okay, first you will need to sync your mind with this program. You will have to answer the following questions to synchronise.\n\n";

        //asks questions
        cout << "Firstly, please enter your full name, with correct capitalisation:\n\n";
        cin >> name;

        cout << "Now please enter the country you are in at the moment:\n\n";
        cin >> country; //<------ Line 32

        cout << "This will be the final question; please provide your age:\n\n";
        cin >> age;

        //asks the user to start the sync
        cout << "There is enough information to start synchronisation. Enter p to start the sync...\n\n";
        string proceed;
        cin >> proceed;
        //checks to see if to proceed and does so
        if (proceed == "p"){
            //provides results of mind read
            cout << "Sync complete." << endl;
            cout << "Your mind has been synced and read.\n\n";
            cout << "However, due to too much interference, only limited data was aquired from your mind." << endl;
            cout << "Here is what was read from your mind:\n\n";

            //puts variables in sentence
            cout << "Your name is " << name << " and you are " << age << " years old. You are based in " << country << "." << endl << "\n\n";

            cout << "Thanks for using Mind Reader, have a nice day. Enter e to exit." << endl;
            //terminates the program the program
            string terminate;
            cin >> terminate;
            if (terminate == "e"){
                exit(0);
            }

        }

    }
    //terminates the program if the input is 'n'
    if (exitOrNot == "n"){
        exit(0);
    }

    return 0;
}

編集:実行すると次のようになります。

                     @@@@@@@@@@@@-MIND READER-@@@@@@@@@@@@

Would like you to have your mind read? Enter y for yes and n for no.
If you do not choose to proceed, this program will terminate.
y
Okay, first you will need to sync your mind with this program. You will have to
answer the following questions to synchronise.

Firstly, please enter your full name, with correct capitalisation:

John Smith
Now please enter the country you are in at the moment:

This will be the final question; please provide your age:

13
There is enough information to start synchronisation. Enter p to start the sync.
..

p
Sync complete.
Your mind has been synced and read.

However, due to too much interference, only limited data was aquired from your m
ind.
Here is what was read from your mind:

Your name is John and you are 13 years old. You are based in Smith.


Thanks for using Mind Reader, have a nice day. Enter e to exit.
e

Process returned 0 (0x0)   execution time : 78.220 s
Press any key to continue.

そして、ここにそれをより明確にするためのスクリーンショットがあります: http://puu.sh/4QZb3.png この投稿には添付できません。

ユーザーの姓を国としてどのように使用するかも注目に値します。問題は、入力が整数ではないことに関係していると思います。

ありがとう。

4

4 に答える 4

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上記のユーザーが言ったことは、cin では、cin ごとに文字列に入力できる単語は 1 つだけです。したがって、あなたが望むものは次のようになると思います: getline(cin, name)

于 2013-10-15T20:52:05.147 に答える