0

次のようなテーブルがあります。

Value            Name

ProjectA       ProjectName
10/10/2012     StartDate
10/10/2013     EndDate
ProjectB       ProjectName
11/11/2012     StartDate
11/11/2013     EndDate
ProjectC       ProjectName
12/12/2012     StartDate
12/12/2013     EndDate

テーブルを次のように変更する必要があります。

Project Name           Start Date           End Date

ProjectA               10/10/2012          10/10/2013 
ProjectB               11/11/2012          11/11/2013 
ProjectC               12/12/2012          12/12/2013

次のクエリを使用して結果を達成しました。

select * from Project 
pivot
(
max(Value)
for[Name] in ([Project Name],[Start Date],[End Date])
)piv

これを実行すると、次のような結果が得られます。

 Project Name     Start Date      End Date

    Project C           12/12/2012  12/12/2013

クエリでどのような間違いをしましたか?

4

1 に答える 1

2

The problem relates to the Max(Value) it will only return the highest value, Pivot is not really designed to do non aggregation values.

This should however solve your issue.

    WITH CTE(Value, Name,RID)
    AS
    (
    SELECT Value, Name, ROW_NUMBER() OVER (PARTITION BY (Name)ORDER BY Value) AS RID FROM  YOURTABLE --Replace 
    )
    SELECT [ProjectName],[StartDate],[EndDate]
    FROM
    (SELECT Value,Name,RID
    FROM CTE)C
    PIVOT
    (
    max(Value)
    FOR Name IN ([ProjectName],[StartDate],[EndDate])
    ) AS PivotTable;

It worked on my instance here with your test data.

Edit: Dynamic Request

I am not that good with Dynamic SQL and I am unable to get the columns to order correctly, although this is just due to the way it groups the column names in desc order.

DECLARE @columns NVARCHAR(MAX), @sql NVARCHAR(MAX);
SET @columns = N'';
SELECT @columns += N'' + QUOTENAME(Name) + ', '
    FROM TestTable
    GROUP BY Name

Set @columns = LEFT(@Columns,Len(@Columns) -1)
Print @columns

SET @sql = N'
WITH CTE(Value, Name,RID)
AS
(
SELECT Value, Name, ROW_NUMBER() OVER (PARTITION BY (Name)  ORDER BY Value) AS RID FROM TestTable
)   
SELECT  ' + @columns + '
FROM
(SELECT Value,Name,RID
FROM CTE)C
PIVOT
(
max(Value)
FOR Name IN (' + @columns + ' )
) AS PivotTable;';
PRINT @sql;
EXEC sp_executesql @sql;
于 2013-10-16T15:44:53.920 に答える