1

次のスクリプトがあります。

drop view proba;
create view proba as
select distinct oper as p_name
, sum(duration) as out_duration 
from TA_OUT 
where oper in ('CZE','FRA')
and timestamp like '201306%' 
group by oper;

drop view proba1;
create view proba1 as
select distinct oper as p_name
,sum(duration) as in_duration 
from TA_IN 
where oper in ('CZE','FRA')
and timestamp like '201306%'
group by oper;

drop view proba3; 
create view proba3 as
select distinct oper as p_name
,sum(duration) as out_duration 
from TA_OUT
where oper in ('CZE','FRA')
and timestamp like '201305%' 
group by oper;

drop view proba4;
create view proba4 as
select distinct oper as p_name
,sum(duration) as in_duration 
from TA_IN 
where oper in ('CZE','FRA')
and timestamp like '201305%'
group by oper;

drop view proba2;
create view proba2 as
select distinct oper as p_name 
from OPER_DESCRIPTION;

このコードの考え方は、異なる月の期間を受け取り、その後次のコードでこの期間を比較することです。これが次のコードです。

drop view proba5;

CREATE VIEW proba5 AS
SELECT (BAL1 + BAL2) AS BAL
FROM 
(
    SELECT 
        CASE

            WHEN proba.out_duration <= proba1.in_duration
             AND proba.p_name IN ('CZE', 'FRA')
             AND proba1.p_name IN ('CZE', 'FRA')
            THEN (proba.out_duration / 60) * 0.14

            WHEN proba.out_duration > proba1.in_duration
             AND proba.p_name IN ('CZE', 'FRA')
             AND proba1.p_name IN ('CZE', 'FRA')
            THEN
                (proba1.in_duration / 60) * 0.14
                +
                ((proba.out_duration - proba1.in_duration) / 60) * 0.09

            ELSE 0

        END AS BAL1

        , CASE

            WHEN proba3.out_duration <= proba4.in_duration
             AND proba3.p_name IN ('CZE', 'FRA')
             AND proba4.p_name IN ('CZE', 'FRA')
            THEN (proba3.out_duration / 60) * 0.14

            WHEN proba3.out_duration > proba4.in_duration
             AND proba3.p_name IN ('CZE', 'FRA')
             AND proba4.p_name IN ('CZE', 'FRA')
            THEN
                (proba4.in_duration / 60) * 0.14
                + ((proba3.out_duration - proba4.in_duration) / 60) * 0.09

            ELSE 0

        END AS BAL2

    FROM 
    (
        (
            (
                (
                    proba2
                    LEFT JOIN proba
                        ON proba2.p_name = proba.p_name
                )
                LEFT JOIN proba1
                    ON proba1.p_name = proba1.p_name
                LEFT JOIN proba3
                    ON proba3.p_name = proba3.p_name
            )
            LEFT JOIN proba4
                ON proba4.p_name = proba4.p_name
        )
        WHERE proba.p_name IN ('CZE', 'FRA')
        AND proba1.p_name IN ('CZE', 'FRA')
        AND proba3.p_name IN ('CZE', 'FRA')
        AND proba4.p_name IN ('CZE', 'FRA')
    )
);

たとえば「CZE」などの 1 つの p_name を使用すると、正しい合計期間が表示されます。P_name ごとに個別の期間を受け取りたいです。例えば：

CZE 500
FRA 1300

ただし、問題は、期間によるグループも含める必要があるため、p_name のみでグループ化できないことです。

この問題を解決する方法を教えてください。

4

2 に答える 2

1

これをチェックしてください：

CREATE VIEW proba5
AS
SELECT p_name, SUM(BAL1 + BAL2) 
FROM (
    SELECT
        proba.p_name, 
        CASE
            WHEN     proba.out_duration <= proba1.in_duration
                THEN     proba.out_duration / 60) * 0.14
            WHEN     proba.out_duration > proba1.in_duration
                THEN     (proba1.in_duration / 60) * 0.14
                       + ((proba.out_duration - proba1.in_duration)/60) * 0.09
            ELSE 0
        END AS BAL1,
        CASE
            WHEN     proba3.out_duration <= proba4.in_duration
                THEN  (proba3.out_duration / 60) * 0.14
            WHEN     proba3.out_duration > proba4.in_duration
                THEN    (proba4.in_duration / 60) * 0.14
                       + ((proba3.out_duration - proba4.in_duration)/60) * 0.09
            ELSE 0
        END AS BAL2
    FROM proba2
        LEFT JOIN proba  ON proba2.p_name = proba.p_name
        LEFT JOIN proba1 ON proba1.p_name = proba1.p_name
        LEFT JOIN proba3 ON proba3.p_name = proba3.p_name
        LEFT JOIN proba4 ON proba4.p_name = proba4.p_name
    WHERE     
        proba.p_name IN ('CZE', 'FRA')
    AND proba1.p_name IN ('CZE', 'FRA')
    AND proba3.p_name IN ('CZE', 'FRA')
    AND proba4.p_name IN ('CZE', 'FRA')
)
    GROUP BY proba.p_name;
于 2013-10-19T02:38:18.083 に答える
1

以下のコードは、組み合わされたすべてのビューが試みていることを実行する必要があると思います/何が起こっているのかを簡単に確認できることを願っています:

create view probAll as
select coalesce(tin.oper,tout.oper) as p_name
, sum
    (
        0.14 * tout.duration / 60 
        + case 
            when tout.duration > tin.duration
            then 0.09 * (tout.duration - tin.duration) / 60
            else 0
        end
    )
from 

(
    select oper
    , EXTRACT(Year FROM DATE timestamp) as tYear
    , EXTRACT(Month FROM DATE timestamp) as tMonth
    , sum(duration) as Balance
    from TA_OUT
    group by oper
    , EXTRACT(Year FROM DATE timestamp)
    , EXTRACT(Month FROM DATE timestamp) 
) as tout

full outer join

(    
    select oper
    , EXTRACT(Year FROM DATE timestamp) as tYear
    , EXTRACT(Month FROM DATE timestamp) as tMonth
    , sum(duration) as Balance
    from TA_IN
    group by oper
    , EXTRACT(Year FROM DATE timestamp)
    , EXTRACT(Month FROM DATE timestamp) 
) as tin

on tin.oper = tout.oper
and tin.tyear = tout.tyear
and tin.tmonth = tout.tmonth

where coalesce(tin.oper,tout.oper) in ('CZE','FRA')
and coalesce(tin.tyear,tout.tyear) = 2013
and coalesce(tin.tmonth,tout.tmonth) in (5, 6)

group by coalesce(tin.oper,tout.oper)

(未テスト)

于 2013-10-19T03:06:06.527 に答える