php - Mysql 構文は正しいように見えますが、エラー コード 1064 が表示されます

Question

私のエラーは、whereステートメントを挿入する前に機能した1064を返します。from の前または後に where を置きますか?

<?PHP
session_start();

include ("connection.php");

$city = $_POST['city'];

$state = $_POST['state'];

$results = array();
if( $query =  $db->query("SELECT business_id, BusinessName, date, post ".
  "FROM WolfeboroC.posts ". "WHERE city= '$city' && state='$state'".
  "JOIN WolfeboroC.users ON users.recid = posts.business_id ".
  "ORDER BY date DESC LIMIT 0, 500") ) 
{
  while($record = $query->fetch_assoc())
  {
    $results[] = $record;
  }
  $query->close();
}

echo json_encode($results);
?>

Answer 1

"SELECT business_id, BusinessName, date, post ".
"FROM WolfeboroC.posts ". "WHERE city= '$city' && state='$state'".
"JOIN WolfeboroC.users ON users.recid = posts.business_id ".
"ORDER BY date DESC LIMIT 0, 500"

あるべき

"SELECT business_id, BusinessName, date, post ".
"FROM WolfeboroC.posts ". 
"JOIN WolfeboroC.users ON users.recid = posts.business_id ".
"WHERE city= '$city' AND state='$state'".
"ORDER BY date DESC LIMIT 0, 500"

JOIN 動詞は WHERE の前に置く必要があります。