あなたのアプローチは一般的にある程度正しい軌道に乗っていますが、他の人が指摘しているように、いくつかの問題があります。何をすべきか、問題を解決する方法を理解するのに苦労しているようですので、私はあなたのコードを整理し（あちこちでいくつかの編集を行いました）、あなたのコードの編集を詳しく文書化して、あなたが何を理解できるようにしましたアプローチは次のとおりです。
def test():
value=input("Value here!") #eval is bad AND dangerous practice. Avoid using it.
with open ("word-text.txt","r") as f:
#At this point you can do one of two things:
#1) read the entire file line by line
#2) read the entire file into a list, and loop/iterate over that list
#In this example, I'll read the file line by line:
nice_strings = []
for line in f:
line = line.strip() #remove any extraneous whitespace from the line (e.g. spaces and newlines)
nice_str_chars = []
#At this point, you want to read EACH character in the line
#N.B.: ord is the name of a built-in function. Use another name like `char` (below):
for char in line:
#Since you're in this loop, you are dealing with EACH individual character of each line
#And, as you want to "shift" the character by some number of places
#Python doesn't allow you to natively shift strings by arbitrary amounts,
#so, the only way we can do so is to convert EACH character into its numeric representation.
#In order to do so, you have to use the `ord` function which converts characters into
#their respective integer representation.
int_of_char = ord(char)
#At this point, the character has been converted to it's integer equivalent
#NOW, you can "shift" it. In other words, add the value to the `int_of_char`:
int_of_char += value #update the value of the variable
#At this point, the value has been modified, and the INTEGER value of the character has been
#shifted. However, we don't want the shifted INTEGER value: we want the shifted CHARACTER value.
#So, how do we convert integers to characters? Python has a builtin function called `chr` which
#does exactly that.
#So, let's convert the shifted INTEGER to a shifted CHARACTER using `chr`:
nice_char = chr(int_of_char)
#print it out the original and modified characters so you can see what's in the string (this step is optional)
print char, '=>', nice_char
#At this point we've successfully shifted the character. However, since this is just A character of the original
#string, we need a way to save the updated characters as a string. There are a number of ways to do this.
#For simplicity, we can use a list `nice_str_chars`:
nice_str_chars.append(nice_char)
#At this point we've looped over all the characters in ONE LINE, and we've calculated and stored the shifted
#characters for that same line. However, since we've stored the characters in a list: `nice_str_chars`, we
#have to convert it to a string. We can do that using the `join` method on an empty string, with
#`nice_str_chars` as the list (as we want to join the characters of the list into a string):
nice_str = ''.join(nice_str_chars)
#And, since you want to shift ALL the lines, you ought to append the corrected line to a list that can later be
#returned:
nice_strings.append(nice_str)
#you can print it out if necessary:
print line, '=>', nice_str, '\n'
#At this point, you've successfully looped over the entire file, shifted all lines by a user entered integer amount,
#now, all you have to do is return it, or do something else with them (i.e. write the updated strings to another file).
#That part, I'll leave up to you.
return nice_strings
このアプローチの唯一の問題は、値がそれぞれの文字セットの上限を超えるため (出力で明らかになるように)循環的ではないことです(つまり、ループバックしません。たとえばz、shifted by3は になりません)。c以下のセクション）。また、入力した値が非常に大きい場合 (つまり、作業している文字セットの境界よりも大きい場合)、意味不明になります。
ただし、それがあなたの問題の要件であるかどうかはわかりません（以前の質問で示唆されているように、基本的にパスワードの原始的な暗号化を行っているためではないかもしれません）が、それでも言及したいと思いました.
出力：
Value here!2
a => c
p => r
p => r
l => n
e => g
s => u
apples => crrngu
o => q
r => t
a => c
n => p
g => i
e => g
s => u
oranges => qtcpigu
w => y
a => c
t => v
e => g
r => t
m => o
e => g
l => n
o => q
n => p
watermelon => ycvgtognqp
k => m
i => k
w => y
i => k
kiwi => mkyk
z => |
u => w
c => e
c => e
h => j
i => k
n => p
i => k
zucchini => |weejkpk
c => e
a => c
r => t
r => t
o => q
t => v
carrot => ecttqv
o => q
k => m
r => t
a => c
okra => qmtc
j => l
a => c
l => n
a => c
p => r
e => g
n => p
o => q
jalapeno => lcncrgpq
p => r
e => g
p => r
p => r
e => g
r => t
pepper => rgrrgt
c => e
u => w
c => e
u => w
m => o
b => d
e => g
r => t
cucumber => ewewodgt
b => d
a => c
n => p
a => c
n => p
a => c
banana => dcpcpc