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Web にログインする Android アクティビティを適切にコーディングする方法に関する私の間違いを修正するのを手伝ってください。正常にログインすると、その Web ポータルのコンテンツの表示を開始できますか?

これが私の未完成のコードです。間違いを修正してください。前もって感謝します!

package com.example.weblogin;


import java.util.ArrayList;
import java.util.List;

import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;


public class LoginActivity extends Activity implements OnClickListener {

    private ProgressDialog pDialog; // Progress Dialog
    private static final String LOGIN_URL = "http://vo.aimglobalinc.com/control/con_login.asp";
    JSONParser jsonParser = new JSONParser(); // JSON parser class

    private static final String TAG_SUCCESS = "success";
    private static final String TAG_MESSAGE = "message";

    private EditText user, pass;
    private Button mSubmit, mRegister;


@Override
protected void onCreate(Bundle savedInstanceState) {
    //requestWindowFeature(Window.FEATURE_NO_TITLE);
    //getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN, 
            //WindowManager.LayoutParams.FLAG_FULLSCREEN);
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_login);

    // get intent data
    Intent i1 = getIntent();
    // Selected image id
    i1.getExtras().getInt("login");
    setResult(RESULT_OK, i1);

  //setup input fields
    user = (EditText)findViewById(R.id.txt_username);
    pass = (EditText)findViewById(R.id.txt_password);
  //setup buttons
    mSubmit = (Button)findViewById(R.id.btn_login);
    mRegister = (Button)findViewById(R.id.btn_register);
  //register listeners
    mSubmit.setOnClickListener(this);
    mRegister.setOnClickListener(this);

}

        @Override
        public void onClick(View v) {

            switch (v.getId()) {
            case R.id.btn_login:
                new AttemptLogin().execute();
                break;
            case R.id.btn_register:
                //Intent i = new Intent(this, RegisterActivity.class);
                //startActivity(i);
                break;
            default:
                break;
            }
        }


        class AttemptLogin extends AsyncTask<String, String, String> {
            //three methods get called, first preExecture, then do in background, and once do
            //in back ground is completed, the onPost execture method will be called.

            /**
            * Before starting background thread Show Progress Dialog
            * */
            boolean failure = false;

            @Override
            protected void onPreExecute() {
                super.onPreExecute();
                pDialog = new ProgressDialog(LoginActivity.this);
                pDialog.setMessage("Attempting login...");
                pDialog.setIndeterminate(false);
                pDialog.setCancelable(true);
                pDialog.show();

            }
            @Override
            protected String doInBackground(String... args) {
                // TODO Auto-generated method stub
                // Check for success tag
                int success;
                String username = user.getText().toString();
                String password = pass.getText().toString();

                try {
                    // Building Parameters
                    List<NameValuePair> params = new ArrayList<NameValuePair>();
                    params.add(new BasicNameValuePair("uname", username));
                    params.add(new BasicNameValuePair("pword", password));

                    Log.d("request!", "starting");
                    // getting product details by making HTTP request
                    JSONObject json = jsonParser.makeHttpRequest(
                        LOGIN_URL, "POST", params);
                    // check your log for json response
                    Log.d("Login attempt", json.toString());
                    // json success tag
                    success = json.getInt(TAG_SUCCESS);
                    if (success == 1) {
                        Log.d("Login Successful!", json.toString());
                        //Toast.makeText(LoginActivity.this, "Login Successful!", Toast.LENGTH_LONG).show();
                        //Intent i = new Intent(LoginActivity.this, PortalContents.class);
                        finish();
                        //startActivity(i);
                        return json.getString(TAG_MESSAGE);
                    }else{
                        Log.d("Login Failure!", json.getString(TAG_MESSAGE));
                        //Toast.makeText(LoginActivity.this, "Login Fail!", Toast.LENGTH_LONG).show();
                        return json.getString(TAG_MESSAGE);
                    }
                } catch (JSONException e) {
                    e.printStackTrace();
                }

                return null;

            }
            /**
            * After completing background task Dismiss the progress dialog
            * **/

            protected void onPostExecute(String file_url) {
                // dismiss the dialog once product deleted
                pDialog.dismiss();
                if (file_url != null){
                    Toast.makeText(getApplicationContext(), file_url, Toast.LENGTH_LONG).show();

                }


            }


        }

}
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1 に答える 1

0

ログイン資格情報が正しい場合に応答を返すように、サーバー (たとえば、ローカル IIS サーバー) を構成する必要があります。

私のログインAsyncTaskコード: -

private class GetLogin extends AsyncTask<Void, Void, Void> {


        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            response = null;
            try {
                progressDialog = new ProgressDialog(Login.this, android.R.style.Theme_Holo_Light_Dialog);
                progressDialog.setMessage("Please wait...");
                progressDialog.setOnCancelListener(new OnCancelListener() {

                    @Override
                    public void onCancel(DialogInterface dialog) {

                        if(getLogin !=null && getLogin.getStatus() != AsyncTask.Status.FINISHED){
                            getLogin.cancel(true);
                        }

                    }
                });
                progressDialog.show();
            } catch (Exception e) {
            }
        }

        protected Void doInBackground(Void... params) {


            try{
                String deviceId = CommonString.deviceId;
                String buildVesrsion = CommonString.buildVersion;
                HashMap<String, String> map = new HashMap<String, String>();
                map.put("email", edtEmail.getText().toString().trim());
                map.put("password", edtPassword.getText().toString().trim());
                map.put("deviceID", deviceId);
                map.put("buildV", buildVesrsion);
                map.put("Platform", CommonString.en);
                map.put("deviceTokenId", regId);
                response = CommonFunction.PostRequest("login", map);
            }catch(Exception e){
                response = null;
            }


            return null;
        }

        @Override
        protected void onCancelled() {
        }
        @Override
        protected void onPostExecute(Void result) {

            if(response != null && !response.equals("")){
                parseResponse(response);
            }else{

                if(progressDialog != null & progressDialog.isShowing()){
                    progressDialog.dismiss();
                }

                Toast.makeText(getApplicationContext(), CommonString.NO_NETWORK, Toast.LENGTH_SHORT).show();
            }

        }
    }

サーバーから「応答」を取得し、この関数を使用して解析します:-

private void parseResponse(String responce) {
try {


    JSONObject object = new JSONObject(responce);
    rCode = Integer.parseInt(object.getString("rcode"));
    switch (rCode) {

    case 100: // If respose is true do here
        isLoginCorrect = true;
        JSONObject data = object.getJSONObject("data");
        JSONObject userInfo = data.getJSONObject("userInfo");
        break;
    case 101: // Different errors based on the errors you have defined in your server
        isLoginCorrect = false;
        message = object.getString("msg");
        handler.sendEmptyMessage(0);
        break;
    case 102:
        isLoginCorrect = false;
        message = object.getString("msg");
        Toast.makeText(Login.this.getApplicationContext(), "There seems to be some trouble with your account, please login again.", Toast.LENGTH_SHORT).show();
        handler.sendEmptyMessage(0);
        break;
    case 103:
        isLoginCorrect = false;
        message = object.getString("msg");
        handler.sendEmptyMessage(0);
        break;
    case 104:
        isLoginCorrect = false;
        message = object.getString("msg");
        handler.sendEmptyMessage(0);
        break;
    case 105:
        isLoginCorrect = false;
        message = object.getString("msg");
        handler.sendEmptyMessage(0);
        break;
    default:
        break;
    }

} catch (Exception e) {
    e.printStackTrace();
    isLoginCorrect = false;


}
    }

このようなことができます。

于 2013-10-29T11:48:05.740 に答える