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日付から指定された日数を引いた値を返すバッチ ファイルがあります。

例: 09/11/2013 の場合、08/11/2013batch.bat today -1 が返されます。

週末の場合は、金曜日の日付が返されます。

問題は、引数を入力せずにバッチに最後の営業日を与えようとしたが失敗したことです

コードは次のとおりです。

@echo off
if "%~2"=="" (
echo to get yesterdays date use     call "%~n0" today -1
echo.
echo Add a third parameter if you want a separator in the date string
echo EG: for this format YYYY-MM-DD using yesterdays date
echo     call "%~n0" today -1 -
echo.
pause
goto :EOF)

set date1=%1
set qty=%2
set separator=%~3
if /i "%date1%" EQU "TODAY" (set date1=now) else (set date1="%date1%")
echo >"%temp%\%~n0.vbs" s=DateAdd("d",%qty%,%date1%)
echo>>"%temp%\%~n0.vbs" d=weekday(s)
echo>>"%temp%\%~n0.vbs" WScript.Echo year(s)^&_
echo>>"%temp%\%~n0.vbs"         right(100+month(s),2)^&_
echo>>"%temp%\%~n0.vbs"         right(100+day(s),2)^&_
echo>>"%temp%\%~n0.vbs"         d
for /f %%a in ('cscript //nologo "%temp%\%~n0.vbs"') do set result=%%a
del "%temp%\%~n0.vbs"
endlocal& set "YY=%result:~0,4%" & set "MM=%result:~4,2%" & set "DD=%result:~6,2%" & set "daynum=%result:~-1%"
:: if the daynum is a weekend then run the batch file again to get the friday
set "weekend="
if %daynum% EQU 1 set /a weekend=qty - 2
if %daynum% EQU 7 set /a weekend=qty - 1
if defined weekend %0 %1 %weekend%

set "day=%YY%%separator%%MM%%separator%%DD%"
echo %%day%% is set to "%day%" (without the quotes)
echo %%YY%% is set to %YY%
echo %%MM%% is set to %MM%
echo %%DD%% is set to %DD%
echo.
echo daynum is "%daynum%"
echo date is %YY%%MM%%DD%
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1 に答える 1

0 
@echo off
set qty=-1
:loop4weekends
set "separator="
echo >"%temp%\%~n0.vbs" s=DateAdd("d",%qty%,now)
echo>>"%temp%\%~n0.vbs" d=weekday(s)
echo>>"%temp%\%~n0.vbs" WScript.Echo year(s)^&_
echo>>"%temp%\%~n0.vbs"         right(100+month(s),2)^&_
echo>>"%temp%\%~n0.vbs"         right(100+day(s),2)^&_
echo>>"%temp%\%~n0.vbs"         d
for /f %%a in ('cscript //nologo "%temp%\%~n0.vbs"') do set result=%%a
del "%temp%\%~n0.vbs"
endlocal& set "YY=%result:~0,4%" & set "MM=%result:~4,2%" & set "DD=%result:~6,2%" & set "daynum=%result:~-1%"
:: if the daynum is a weekend then loop to get the friday
set "weekend="
if %daynum% EQU 1 set weekend=1&set "qty=-3"
if %daynum% EQU 7 set weekend=1&set "qty=-2"
if defined weekend goto :loop4weekends

set "day=%YY%%separator%%MM%%separator%%DD%"
echo %%day%% is set to "%day%" (without the quotes)
于 2013-11-12T08:47:36.717 に答える