0

次のデータについて、SQL で完了率の列を取得しようとしています。これは私のクエリの結果です。

work_order_no status        orderqty        complete precentcomplete
WO-000076     Approved      20.0000         9        5201725
WO-000076     Approved      20.0000         10       15605175
WO-000078     Approved      12000.0000      200      91258.3333333333
WO-000078     Approved      12000.0000      500      228145.833333333

私が必要とするのは、2行の結果です。行 1 は WO-00076 で、完了率です。行 2 は WO-000078 で、完了率です。以下は、私が取り組んでいるクエリです。

 Select distinct wo.work_order_no,
                wos.status_description,
                wo.order_qty as [ORDERQTY],
                p.good_tot_diff as [COMPLETE],
                (sum(p.good_tot_diff)/wo.order_qty) * 100 as [PERCENTCOMPLETE]
from wo_master as wo,
     process as p,
     wo_statuses as wos,
     so_children as soc,
     so_sales_orders as sos,
     cs_customers as csc
where wo.work_order_no = p.entry_18_data_txt
and wo.work_order_no = soc.work_order_no
and wo.wo_status_id = wos.wo_status_id
and wo.mfg_building_id = @buildid
and wos.wo_status_id = @statusid
group by wo.work_order_no, wos.status_description, wo.order_qty, p.good_tot_diff

だから私は結果が以下のようになることを望みます

work_order_no status        orderqty        complete precentcomplete
WO-000076     Approved      20.0000         19       0.95
WO-000078     Approved      12000.0000      700      0.005
4

3 に答える 3

0

これを試して：

Select wo.work_order_no,
    wos.status_description,
    wo.order_qty as [ORDERQTY],
    SUM(p.good_tot_diff) as [COMPLETE],
    SUM(p.good_tot_diff)/wo.order_qty as [PERCENTCOMPLETE]
from wo_master as wo,
    process as p,
    wo_statuses as wos,
    so_children as soc,
    so_sales_orders as sos,
    cs_customers as csc
where wo.work_order_no = p.entry_18_data_txt
and wo.work_order_no = soc.work_order_no
and wo.wo_status_id = wos.wo_status_id
and wo.mfg_building_id = @buildid
and wos.wo_status_id = @statusid
group by wo.work_order_no, wos.status_description, wo.order_qty
于 2013-11-13T17:04:28.697 に答える