1

テーブル内のすべてに対して単一のレコードを返すのではなく、毎年のレコードを返すようにこのクエリを取得しようとしています。

SELECT 
    JAN
    , FEB
    , MAR
    , APR
    , MAY
    , JUN
    , JUL
    , AUG
    , SEP
    , OCT
    , NOV
    , [DEC]
    ,JAN + FEB + MAR + APR + MAY + JUN + JUL + AUG + SEP + OCT + NOV + [DEC] AS TOTAL
    FROM
    (SELECT DISTINCT
        (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 1) AS JAN
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 2) AS FEB
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 3) AS MAR
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 4) AS APR
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 5) AS MAY
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 6) AS JUN
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 7) AS JUL
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 8) AS AUG
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 9) AS SEP
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 10) AS OCT
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 11) AS NOV
        , (SELECT COUNT(*) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 12) AS [DEC]
    FROM RET.tbl_Record)x

これは1つのレコードを返します(それが想定されていることを知っています)が、毎年のレコードを返したいと思います。これを達成する方法がわかりません。

編集:

SELECT 
    JAN
    , FEB
    , MAR
    , APR
    , MAY
    , JUN
    , JUL
    , AUG
    , SEP
    , OCT
    , NOV
    , [DEC]
    ,JAN + FEB + MAR + APR + MAY + JUN + JUL + AUG + SEP + OCT + NOV + [DEC] AS TOTAL
    FROM
    (SELECT
        (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 1) AS JAN
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 2) AS FEB
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 3) AS MAR
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 4) AS APR
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 5) AS MAY
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 6) AS JUN
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 7) AS JUL
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 8) AS AUG
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 9) AS SEP
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 10) AS OCT
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 11) AS NOV
        , (SELECT COUNT(dt_updated) FROM RET.tbl_Record WHERE MONTH(dt_updated) = 12) AS [DEC]
    FROM RET.tbl_Record
    GROUP BY YEAR(dt_updated))x

探しているレコードの正しい量である 3 つのレコードを返すようになりましたが、各レコードは同じ値を返します (各レコードの 3 年すべてをカウントします)。

4

3 に答える 3

0

タスクを達成するためのより効率的な方法を望んでいましたが、解決策は次のようになります。

SELECT
      JAN.dtyear AS [YEAR]
    , ISNULL(JAN.TOTAL, 0) AS JAN
    , ISNULL(FEB.TOTAL, 0) AS FEB
    , ISNULL(MAR.TOTAL, 0) AS MAR
    , ISNULL(APR.TOTAL, 0) AS APR
    , ISNULL(MAY.TOTAL, 0) AS MAY
    , ISNULL(JUN.TOTAL, 0) AS JUN
    , ISNULL(JUL.TOTAL, 0) AS JUL
    , ISNULL(AUG.TOTAL, 0) AS AUG
    , ISNULL(SEP.TOTAL, 0) AS SEP
    , ISNULL(OCT.TOTAL, 0) AS OCT
    , ISNULL(NOV.TOTAL, 0) AS NOV
    , ISNULL([DEC].TOTAL, 0) AS [DEC]
    , ISNULL(JAN.TOTAL, 0) + ISNULL(FEB.TOTAL, 0) + ISNULL(MAR.TOTAL, 0) + ISNULL(APR.TOTAL, 0) + ISNULL(MAY.TOTAL, 0) + ISNULL(JUN.TOTAL, 0) + ISNULL(JUL.TOTAL, 0) + ISNULL(AUG.TOTAL, 0) + ISNULL(SEP.TOTAL, 0) + 
        ISNULL(OCT.TOTAL, 0) + ISNULL(NOV.TOTAL, 0) + ISNULL([DEC].TOTAL, 0) AS TOTAL
FROM 
    (SELECT COUNT(RET_record_id) as TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 1 GROUP BY YEAR(dt_updated)) JAN
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) as TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 2 GROUP BY YEAR(dt_updated)) FEB
     ON JAN.dtyear = FEB.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 3 GROUP BY YEAR(dt_updated)) MAR
     ON JAN.dtyear = MAR.dtyear AND FEB.dtyear = MAR.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 4 GROUP BY YEAR(dt_updated)) APR
     ON JAN.dtyear = APR.dtyear
    LEFT OUTER JOIN 
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 5 GROUP BY YEAR(dt_updated)) MAY
     ON JAN.dtyear = MAY.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 6 GROUP BY YEAR(dt_updated)) JUN
     ON JAN.dtyear = JUN.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 7 GROUP BY YEAR(dt_updated)) JUL
     ON JAN.dtyear = JUL.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 8 GROUP BY YEAR(dt_updated)) AUG
     ON JAN.dtyear = AUG.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 9 GROUP BY YEAR(dt_updated)) SEP
     ON JAN.dtyear = SEP.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 10 GROUP BY YEAR(dt_updated)) OCT
     ON JAN.dtyear = OCT.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 11 GROUP BY YEAR(dt_updated)) NOV
     ON JAN.dtyear = NOV.dtyear
    LEFT OUTER JOIN
    (SELECT COUNT(RET_record_id) AS TOTAL, YEAR(dt_updated) AS dtyear FROM RET.tbl_Record WHERE MONTH(dt_updated) = 12 GROUP BY YEAR(dt_updated)) [DEC]
     ON JAN.dtyear = [DEC].dtyear
于 2013-11-14T00:58:16.163 に答える
0

多分 :

GROUP BY YEAR(dt_updated)

于 2013-11-13T23:57:47.457 に答える