1

I have got simple query

WITH  conn_cte ( ParentCategoryId, CategoryId, IdsPath )
        AS ( SELECT ParentCategoryId
                   ,CategoryId
                   ,CAST(ParentCategoryId AS varchar(1000))
             FROM   Ind_CategoriesConnections
             WHERE  ParentCategoryId = 0
             UNION ALL
             SELECT cc.ParentCategoryId
                   ,cc.CategoryId
                   ,CAST(IdsPath + ','
                    + CAST (cc.ParentCategoryId AS varchar(5)) AS varchar(1000))
             FROM   Ind_CategoriesConnections AS cc
                    INNER JOIN conn_cte AS conn ON conn.CategoryId = cc.ParentCategoryId
                                                   AND cc.categoryid NOT IN (
                                                   SELECT conn.Categoryid )
           )
  SELECT  x.*
  FROM    ( SELECT  t.ParentCategoryId
                   ,t.CategoryId
                   ,t.IdsPath + ',' + CAST(t.CategoryId AS varchar(5)) AS [path]
            FROM    conn_cte t
                    INNER JOIN Ind_Categories c ON t.CategoryId = c.CategoryId
                                                   AND c.CategoryViewId = 1
                                                   AND c.IsActiveYN = 1
          ) x
  ORDER BY x.path

I am interesting in query (optimal) that only return full paths from root to leaf.

たとえば、結果の一部は

Parent  Child   Path
12       16     0,8,12,16
16       17     0,8,12,16,17
17       18     0,8,12,16,17,18
17       19     0,8,12,16,17,19

ゼロはルート 18,19 はリーフ (および子) です。 and のようなパスを部分的に無視し、完全なパス (リーフで終了) のみを取得 したいと思います0,8,12,16。0,8,12,16,170,8,12,16,17,180,8,12,16,17,19

4

2 に答える 2

1

次のように言えます。

WHERE NOT EXISTS (SELECT * FROM conn_cte AS parents WHERE t.path LIKE parents.path + '%')
于 2010-01-04T23:12:41.637 に答える