angularjs - Angular 2 の $scope と splice。1 つを他の $scope と同等にする方法は?

Question

問題はこれです：

$scope.model1 = [1,2,3,4,5,6,7];
$scope.model2 =  $scope.model1;

$scope.model2.splice(2, 1);

 <pre>{{model1}}</pre>
 <pre>{{model2}}</pre>

戻る：

[1,2,4,5,6,7]
[1,2,4,5,6,7]

必要：

 [1,2,3,4,5,6,7]
 [1,2,4,5,6,7]

なぜこうなった？

更新: 解決策:どこでも使用angular.copy($scope.val) 私のコードが悪い:

$scope.$watch('checkedImages', function (newVal) {
        if (newVal !== undefined && newVal[0] !== undefined) {
            if ($scope.model.curSupplier === undefined) {
                $scope.model.curSupplier = newVal[0].supplier_id;
                $scope.model.curCheckedImages = newVal;
            }
            $scope.supplier = newVal[0].supplier_id;
        }
    });

対

$scope.$watch('checkedImages', function (newVal) {
    if (newVal !== undefined && newVal[0] !== undefined) {
        if ($scope.model.curSupplier === undefined) {
            $scope.model.curSupplier = angular.copy(newVal[0].supplier_id);
            $scope.model.curCheckedImages =  angular.copy(newVal);
        }
        $scope.supplier =  angular.copy(newVal[0].supplier_id);
    }
});