0

私はこれらの2つのテーブルを持っています

CREATE TABLE [dbo].[Things](
    [testid] [int] NOT NULL,
    [testdesc] [varchar](10) NULL
) ON [PRIMARY]

CREATE TABLE [dbo].[ThingsStaging](
    [otherid] [int] NOT NULL,
    [testid] [int] NOT NULL
) ON [PRIMARY]

INSERT INTO [dbo].[Things] ([testid], [testdesc]) VALUES (1, N'Stuff')
INSERT INTO [dbo].[Things] ([testid], [testdesc]) VALUES (2, N'Things')
INSERT INTO [dbo].[Things] ([testid], [testdesc]) VALUES (3, N'Orcs')
INSERT INTO [dbo].[Things] ([testid], [testdesc]) VALUES (4, N'Grubs')
INSERT INTO [dbo].[Things] ([testid], [testdesc]) VALUES (5, N'Shrooms')

INSERT INTO [dbo].[ThingsStaging] ([otherid], [testid]) VALUES (1, 1)
INSERT INTO [dbo].[ThingsStaging] ([otherid], [testid]) VALUES (1, 2)
INSERT INTO [dbo].[ThingsStaging] ([otherid], [testid]) VALUES (1, 3)
INSERT INTO [dbo].[ThingsStaging] ([otherid], [testid]) VALUES (2, 3)
INSERT INTO [dbo].[ThingsStaging] ([otherid], [testid]) VALUES (2, 4)

;with allThings(otherid, descs)
as 
(
    select ts.otherid ,
    stuff ((select ', ' + blah.testdesc  as [text()]
            from (
                select distinct t.testdesc 
                from Things as t
                where t.testid = ts.testid ) as blah 
                for xml path('')), 1, 1, '') as stuffs
    from ThingsStaging as ts 
)
select *
from allThings

このクエリを実行すると、

otherid stuffs
1    Stuff
1    Things
1    Orcs
2    Orcs
2    Grubs

しかし、私は取得する必要があります:

otherid     stuffs
1     Stuff, Things, Orcs
2     Orcs, Grubs

私は自分が間違っていることを理解していません。

4

1 に答える 1

0

私が間違ったことを理解しています。コードはよりよく説明します。

select otherid, stuff((select ', ' + t.testdesc as [text()]
                        from Things as t
                        inner join ThingsStaging as its on t.testid = its.testid
                        where its.otherid = ts.otherid
                        for xml path('')), 1, 1, '') as descs
from ThingsStaging as ts
group by otherid
于 2014-01-10T19:16:46.880 に答える