17

誰かが次の PostMark curl の例を pycurl に変換できますか?

curl -X POST "http://api.postmarkapp.com/email" \

-H "Accept: application/json" \

-H "Content-Type: application/json" \

-H "X-Postmark-Server-Token: ed742D75-5a45-49b6-a0a1-5b9ec3dc9e5d" \

-v \

-d "{From: 'sender@example.com', To: 'receiver@example.com', Subject: 'Postmark test', HtmlBody: '<html><body><strong>Hello</strong> dear Postmark user.</body></html>'}"
4

1 に答える 1

33

このようなものを使用できます。これは基本的な実装ですが、動作するはずです。

import pycurl, json

postmark_url = 'https://api.postmarkapp.com/email'

data = json.dumps({"From": "user@example.com", "To": "receiver@example.com", "Subject": "Pycurl", "TextBody": "Some text"})

c = pycurl.Curl()
c.setopt(pycurl.URL, github_url)
c.setopt(pycurl.HTTPHEADER, ['X-Postmark-Server-Token: API_TOKEN_HERE','Accept: application/json'])
c.setopt(pycurl.POST, 1)
c.setopt(pycurl.POSTFIELDS, data)
c.perform()
于 2014-04-02T14:07:06.327 に答える