wpf - 参照エラー

Question

参照にエラーがある理由がわかりません。OxyPlot.Wpf.LineSeriesto にOxyPlot.Series.Series最適なオーバーロードされたメソッド マッチにSystem.Collections.ObjectModel.Collection.Add(OxyPlot.Axes.Axis)は、いくつかの無効な引数があります。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using OxyPlot;
using OxyPlot.Wpf;
using OxyPlot.Axes;

namespace points
{
   public class PsdTest
    {
       public static PlotModel Filteringinvalidpoints()
       {
           var plotModel1 = new PlotModel();
           plotModel1.Title = "Filtering invalid points";
           var linearAxis1 = new LinearAxis();
           linearAxis1.Position = AxisPosition.Bottom;
           linearAxis1.Title = "X-axis";
           plotModel1.Axes.Add(linearAxis1);
           var linearAxis2 = new LinearAxis();
           linearAxis2.Title = "Y-axis";
           plotModel1.Axes.Add(linearAxis2);
           var lineSeries1 = new LineSeries();
           lineSeries1.Title = "NaN";
           lineSeries1.Points.Add(new DataPoint(double.NaN, double.NaN));
           lineSeries1.Points.Add(new DataPoint(1, 0));
           lineSeries1.Points.Add(new DataPoint(2, 10));
           lineSeries1.Points.Add(new DataPoint(double.NaN, 20));
           lineSeries1.Points.Add(new DataPoint(3, 10));
           lineSeries1.Points.Add(new DataPoint(4, 0));
           lineSeries1.Points.Add(new DataPoint(4.5, double.NaN));
           lineSeries1.Points.Add(new DataPoint(5, 0));
           lineSeries1.Points.Add(new DataPoint(6, 10));
           lineSeries1.Points.Add(new DataPoint(double.NaN, double.NaN));
           lineSeries1.Points.Add(new DataPoint(7, 0));
           lineSeries1.Points.Add(new DataPoint(double.NaN, double.NaN));
           plotModel1.Series.Add(lineSeries1);
           var lineSeries2 = new LineSeries();
           lineSeries2.Title = "PositiveInfinity";
           lineSeries2.Points.Add(new DataPoint(double.PositiveInfinity, double.PositiveInfinity));
           lineSeries2.Points.Add(new DataPoint(1, 1));
           lineSeries2.Points.Add(new DataPoint(2, 11));
           lineSeries2.Points.Add(new DataPoint(double.PositiveInfinity, 20));
           lineSeries2.Points.Add(new DataPoint(3, 11));
           lineSeries2.Points.Add(new DataPoint(4, 1));
           lineSeries2.Points.Add(new DataPoint(4.5, double.PositiveInfinity));
           lineSeries2.Points.Add(new DataPoint(5, 1));
           lineSeries2.Points.Add(new DataPoint(6, 11));
           lineSeries2.Points.Add(new DataPoint(double.PositiveInfinity, double.PositiveInfinity));
           lineSeries2.Points.Add(new DataPoint(7, 1));
           lineSeries2.Points.Add(new DataPoint(double.PositiveInfinity, double.PositiveInfinity));
           plotModel1.Series.Add(lineSeries2);
           var lineSeries3 = new LineSeries();
           lineSeries3.Title = "NegativeInfinity";
           lineSeries3.Points.Add(new DataPoint(double.NegativeInfinity, double.NegativeInfinity));
           lineSeries3.Points.Add(new DataPoint(1, 2));
           lineSeries3.Points.Add(new DataPoint(2, 12));
           lineSeries3.Points.Add(new DataPoint(double.NegativeInfinity, 20));
           lineSeries3.Points.Add(new DataPoint(3, 12));
           lineSeries3.Points.Add(new DataPoint(4, 2));
           lineSeries3.Points.Add(new DataPoint(4.5, double.NegativeInfinity));
           lineSeries3.Points.Add(new DataPoint(5, 2));
           lineSeries3.Points.Add(new DataPoint(6, 12));
           lineSeries3.Points.Add(new DataPoint(double.NegativeInfinity, double.NegativeInfinity));
           lineSeries3.Points.Add(new DataPoint(7, 2));
           lineSeries3.Points.Add(new DataPoint(double.NegativeInfinity, double.NegativeInfinity));
           plotModel1.Series.Add(lineSeries3);
           return plotModel1;
       }

    }
}

Answer 1

異なる名前空間でいくつかの問題が発生しているようです。あなたが何をしようとしているのかを完全に理解しているとは言えません。したがって、これでは望ましい結果が得られない可能性がありますが、次の名前空間を使用してコードをコンパイルすることができました (OxyPlot.Wpf を nuget 経由でインストールしました)。

using OxyPlot;
using OxyPlot.Axes;
using OxyPlot.Series;

OxyPlot.Wpf名前空間で見つかった特定の動作を探していることが判明した場合、これが役に立たない場合があります。