2

SUM()....内で適用できますか?ISNULL()次のSQLServerSelectステートメントを検討してください

SELECT e.Emp_Id,e.Identity_No,e.Emp_Name,case WHEN e.SalaryBasis=1 
THEN 'Weekly' ELSE 'Monthly' end as SalaryBasis,e.FixedSalary,
    ISNULL(Adv.Daily_Wage,0) as Advance from Employee as e 
    inner join Designation as d on e.Desig_Id=d.Desig_Id
    Left Outer Join Payroll as Adv on e.Emp_Id=Adv.Emp_Id where e.Is_Deleted=0 

このステートメントは正常に機能します....しかし、私SUM()ISNULL()

SELECT e.Emp_Id,e.Identity_No,e.Emp_Name,case WHEN e.SalaryBasis=1 
    THEN 'Weekly' ELSE 'Monthly' end as SalaryBasis,e.FixedSalary,
        ISNULL(SUM(Adv.Daily_Wage),0) as Advance from Employee as e 
        inner join Designation as d on e.Desig_Id=d.Desig_Id
        Left Outer Join Payroll as Adv on e.Emp_Id=Adv.Emp_Id 
        where e.Is_Deleted=0 

エラーが発生しました、

列'Employee.Emp_Id'は、集計関数またはGROUP BY句のいずれにも含まれていないため、選択リストでは無効です。

なにか提案を....

4

1 に答える 1

2

selectの他の列でGROUPBYする必要があります。何かのようなもの

SELECT  e.Emp_Id,
        e.Identity_No,
        e.Emp_Name,
        case 
            WHEN e.SalaryBasis=1  THEN 'Weekly' 
            ELSE 'Monthly' 
        end as SalaryBasis,e.FixedSalary, 
        ISNULL(SUM(Adv.Daily_Wage),0) as Advance 
from    Employee as e  inner join 
        Designation as d on e.Desig_Id=d.Desig_Id Left Outer Join 
        Payroll as Adv on e.Emp_Id=Adv.Emp_Id  
where   e.Is_Deleted=0 
GROUP BY e.Emp_Id, --This section is what you are missing
        e.Identity_No,
        e.Emp_Name,
        case 
            WHEN e.SalaryBasis=1  THEN 'Weekly' 
            ELSE 'Monthly' 
        end,
    e.FixedSalary

ここで定義を見てください

GROUP BY(Transact-SQL)

于 2010-02-23T07:44:09.183 に答える