9

I use a URL entered by the user as text to initialize a QUrl object. Later I want to convert the QUrl back into a string for displaying it and to check it using regular expression. This works fine as long as the user does not enter any percent encoded URLs.

Why doesn't the following example code work?

qDebug() << QUrl("http://test.com/query?q=%2B%2Be%3Axyz%2Fen").toDisplayString(QUrl::FullyDecoded);

It simply doesn't decode any of the percent-encoded characters. It should print "http://test.com/query?q=++e:xyz/en" but it actually prints "http://test.com/query?q=%2B%2Be%3Axyz%2Fen".

I also tried a lot of other methods like fromUserInput() but I could not make the code work correctly in Qt5.3.

Can someone explain me how to do this and why the above code doesn't work (i.e. showing the decoded URL) even when using QUrl::FullyDecoded?

UPDATE

After getting the fromPercentEncoding() hint, I tried the following code:

QUrl UrlFromUserInput(const QString& input)
{
   QByteArray latin = input.toLatin1();
   QByteArray utf8 = input.toUtf8();
   if (latin != utf8)
   {
      // URL string containing unicode characters (no percent encoding expected)
      return QUrl::fromUserInput(input);
   }
   else
   {
      // URL string containing ASCII characters only (assume possible %-encoding)
      return QUrl::fromUserInput(QUrl::fromPercentEncoding(input.toLatin1()));
   }
}

This allows the user to input unicode URLs and percent-encoded URLs and it is possible to decode both kinds of URLs for displaying/matching. However the percent-encoded URLs did not work in QWebView... the web-server responded differently (it returned a different page). So obviously QUrl::fromPercentEncoding() is not a clean solution since it effectively changes the URL. I could create two QUrl objects in the above function... one constructed directly, one constructed using fromPercentEncoding(), using the first for QWebView and the latter for displaying/matching only... but this seems absurd.

4

3 に答える 3

3

なぜうまくいかないのかわかりtoDisplayString(QUrl::FullyDecoded)ません。

copy.query(QUrl::FullyDecoded)いくつかのバージョンを試した後、クエリ部分をデコードすることがわかりました。ドキュメントには、デコードされた URL を返す次のコードの例があります。

QUrl url("http://test.com/query?q=%2B%2Be%3Axyz%2Fen");
url.setQuery(url.query(QUrl::FullyDecoded), QUrl::DecodedMode);
qDebug() << url.toString();

クエリ部分が必要なくコピーされるため、この方法で問題を解決することは最適ではありません。

于 2014-06-24T08:25:12.853 に答える
3

この変換にはQUrlQuery::toString(QUrl::FullyEncoded)またはを使用できます。QUrl::fromPercentEncoding()

于 2014-06-21T16:37:17.383 に答える