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マークダウンで記述されたテーブルの値を持っているため、SQL で一時的なプロシージャを作成している最中なので、Web ブラウザーでレンダリングされた HTML として表示されます(マークダウンから HTML への変換)

現在、列の文字列は次のようになっています。

Questions about **general computing hardware and software** are off-topic for Stack Overflow unless they directly involve tools used primarily for programming. You may be able to get help on [Super User](http://superuser.com/about)

現在、太字と斜体のテキストを使用しています。これは、(太字のテキストの場合)**パターンの奇数 N 回をに、偶数回を に置き換える必要があることを意味<b></b>ます。replace()
を見ましたが、文字列のすべてのパターンで置換を実行します。

では、部分文字列が奇数または偶数の場合にのみ、部分文字列を置き換えるにはどうすればよいでしょうか?

更新:一部の人々は、私が使用しているスキーマについて疑問に思っているので、こちらをご覧ください。

必要に応じてもう 1 つ追加します。HTML ハイパーリンクへのマークダウン スタイルのハイパーリンクは、それほど単純に見えません。

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4 に答える 4

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STUFF関数と単純なWHILEループの使用:

CREATE FUNCTION dbo.fn_OddEvenReplace(@text nvarchar(500), 
                                      @textToReplace nvarchar(10), 
                                      @oddText nvarchar(10), 
                                      @evenText nvarchar(500))
RETURNS varchar(max)
AS
BEGIN
    DECLARE @counter tinyint
    SET @counter = 1

    DECLARE @switchText nvarchar(10)
    WHILE CHARINDEX(@textToReplace, @text, 1) > 0
    BEGIN
        SELECT @text = STUFF(@text, 
                    CHARINDEX(@textToReplace, @text, 1), 
                    LEN(@textToReplace), 
                    IIF(@counter%2=0,@evenText,@oddText)),
                @counter = @counter + 1
    END
    RETURN @text
END

そして、次のように使用できます。

SELECT dbo.fn_OddEvenReplace(column, '**', '<b>', '</b>')
FROM table

アップデート:

これは SP として書き直されます。

CREATE PROC dbo.##sp_OddEvenReplace @text nvarchar(500), 
                                  @textToReplace nvarchar(10), 
                                  @oddText nvarchar(10), 
                                  @evenText nvarchar(10),
                                  @returnText nvarchar(500) output
AS
BEGIN
    DECLARE @counter tinyint
    SET @counter = 1

    DECLARE @switchText nvarchar(10)
    WHILE CHARINDEX(@textToReplace, @text, 1) > 0
    BEGIN
        SELECT @text = STUFF(@text, 
                    CHARINDEX(@textToReplace, @text, 1), 
                    LEN(@textToReplace), 
                    IIF(@counter%2=0,@evenText,@oddText)),
                @counter = @counter + 1
    END
    SET @returnText = @text
END
GO

そして実行するには:

DECLARE @returnText nvarchar(500)
EXEC dbo.##sp_OddEvenReplace '**a** **b** **c**', '**', '<b>', '</b>', @returnText output

SELECT @returnText
于 2014-07-31T01:19:03.487 に答える
0

This solution makes use of techniques described by Jeff Moden in this article on the Running Sum problem in SQL. This solution is lengthy, but by making use of the Quirky Update in SQL Server over a clustered index, holds the promise of being much more efficient over large data sets than cursor-based solutions.

Update - amended below to operate off a table of strings

Assuming the existence of a tally table created like this (with at least 8000 rows):

create table dbo.tally (
     N int not null
    ,unique clustered (N desc)
);
go

with 
E1(N) as ( 
    select 1 from (values
        (1),(1),(1),(1),(1),
        (1),(1),(1),(1),(1)
    ) E1(N)
),                                              --10E+1 or 10 rows
E2(N) as (select 1 from E1 a cross join E1 b),  --10E+2 or 100 rows
E4(N) As (select 1 from E2 a cross join E2 b)   --10E+4 or 10,000 rows max
insert dbo.tally(N)
select row_number() over (order by (select null)) from E4;
go

and a HtmlTagSpotter function defined like this:

create function dbo.HtmlTagSPotter(
     @pString       varchar(8000)
    ,@pDelimiter    char(2))
returns table with schemabinding as
return
   WITH 
        Delimiter as (
        select len(@pDelimiter)     as Length,
               len(@pDelimiter)-1   as Offset
    ),
    cteTally(N) AS (
        select top (isnull(datalength(@pstring),0)) 
            row_number() over (order by (select null)) 
        from dbo.tally
    ),
    cteStart(N1) AS (--==== Returns starting position of each "delimiter" )
        select 
            t.N 
        from cteTally t cross join Delimiter 
        where substring(@pString, t.N, Delimiter.Length) = @pDelimiter
    ),
    cteValues as (
        select
             ItemNumber = row_number() over(order by N1)
            ,Location   = N1
        from cteStart
    )
    select
         ItemNumber
        ,Location
    from cteValues
go

then running the following SQL will perform the required substitution. Note that the inner join at the end prevents any trailing "odd" tags from being converted:

create table #t( 
     ItemNo         int             not null
    ,Item           varchar(8000)       null
    ,StartLocation  int             not null
    ,EndLocation    int             not null

    ,constraint PK unique clustered (ItemNo,StartLocation desc)
);

with data(i,s) as ( select i,s from (values
        (1,'Questions about **general computing hardware and software** are off-topic **for Stack Overflow.')
       ,(2,'Questions **about **general computing hardware and software** are off-topic **for Stack Overflow.')
          --....,....1....,....2....,....3....,....4....,....5....,....6....,....7....,....8....,....9....,....0
    )data(i,s)
),
tags as (
    select 
         ItemNo         = data.i
        ,Item           = data.s
        ,Location       = f.Location
        ,IsOpen         = cast((TagNumber % 2) as bit)
        ,Occurrence     = TagNumber
    from data
    cross apply dbo.HtmlTagSPotter(data.s,'**') f
)
insert #t(ItemNo,Item,StartLocation,EndLocation)
select 
     data.ItemNo
    ,data.Item
    ,prev.Location
    ,data.Location
from tags data
join tags prev
   on prev.ItemNo       = data.ItemNo
  and prev.Occurrence = data.Occurrence - 1
  and prev.IsOpen     = 1

union all

select 
    i,s,8001,8002
from data
;

declare @ItemNo     int
       ,@ThisStting varchar(8000);

declare @s varchar(8000);
update this
    set @s = this.Item = case when this.StartLocation > 8000
                              then this.Item
                              else stuff(stuff(@s,this.EndLocation,  2,'</b>')
                                                 ,this.StartLocation,2,'<b>')
                         end
from #t this with (tablockx)
option (maxdop 1);

select
    Item
from (
    select 
         Item
        ,ROW_NUMBER() over (partition by ItemNo order by StartLocation) as rn
    from #t
) t
where rn = 1
go

yielding:

Item
------------------------------------------------------------------------------------------------------------
Questions about <b>general computing hardware and software</b> are off-topic **for Stack Overflow.
Questions <b>about </b>general computing hardware and software<b> are off-topic </b>for Stack Overflow.
于 2014-07-31T03:06:34.750 に答える