Applescript を使用して数字に 3 桁ごとの区切り記号 (コンマ) を入れようとして、非常にクレイジーな時間を過ごしています。おそらくうまくいくと思われる 2 つのサブルーチンをネット上で見つけましたが、何もうまくいっていないようです。
それは私にあらゆる種類のランダムなフォーマットを与えています。整数から実数、短整数、文字列などに変更しようとしましたが、何も役に立たないようです。
私が渡しているもの:
set perCapita2014 to avgHHinc2014 / avgPopHH2014 as integer -- results 17005
呼び出し:
set finalPerCapita2014 to (comma_delimit(perCapita2014)) -- results 0.,0.5
サブルーチン: (明らかに、これらの両方が必要です)
on number_to_string(this_number)
set this_number to this_number as string
if this_number contains "E+" then
set x to the offset of "." in this_number
set y to the offset of "+" in this_number
set z to the offset of "E" in this_number
set the decimal_adjust to characters (y - (length of this_number)) thru ¬
-1 of this_number as string as number
if x is not 0 then
set the first_part to characters 1 thru (x - 1) of this_number as string
else
set the first_part to ""
end if
set the second_part to characters (x + 1) thru (z - 1) of this_number as string
set the converted_number to the first_part
repeat with i from 1 to the decimal_adjust
try
set the converted_number to ¬
the converted_number & character i of the second_part
on error
set the converted_number to the converted_number & "0"
end try
end repeat
return the converted_number
else
return this_number
end if
end number_to_string
on comma_delimit(this_number)
set this_number to this_number as string
if this_number contains "E" then set this_number to number_to_text(this_number)
set the num_length to the length of this_number
set the this_number to (the reverse of every character of this_number) as string
set the new_num to ""
repeat with i from 1 to the num_length
if i is the num_length or (i mod 3) is not 0 then
set the new_num to (character i of this_number & the new_num) as string
else
set the new_num to ("," & character i of this_number & the new_num) as string
end if
end repeat
return the new_num
end comma_delimit