1

webservice のパラメーターを含む get メソッドで webservice を呼び出そうとしています。しかし、私はインターネット上で答えを見つけることができません。

http://api.crmseries.com/user/ValidateUser?email=don@crmSerssies.com&password=visi

4

2 に答える 2

1

これはうまくいくはずです!

public void postData() {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://api.crmseries.com/user/ValidateUser");

try {
    // Add your data
    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
    nameValuePairs.add(new BasicNameValuePair("email", "don@crmSerssies.com"));
    nameValuePairs.add(new BasicNameValuePair("password", "visi"));
    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

    // Execute HTTP Post Request
    HttpResponse response = httpclient.execute(httppost);

} catch (ClientProtocolException e) {
    // TODO Auto-generated catch block
} catch (IOException e) {
    // TODO Auto-generated catch block
}
}
于 2014-08-08T09:14:43.813 に答える
0

これはより良いはずです:)

public void getData(String mEmail, String mPwd) {
        HttpClient httpclient = new DefaultHttpClient();
        HttpGet httpgett = new HttpGet("http://api.crmseries.com/user/ValidateUser?email=" + mEmail + "&password=" + mPwd);

    try {


        // Execute HTTP Post Request
        HttpResponse response = httpclient.execute(httpget);

    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }
    }
于 2014-08-08T09:42:30.510 に答える