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私はpostgreSQL8.3または8.4のいずれかでこの問題を抱えています：

3つの一時シーケンスを（再）作成し、それらを使用していくつかのテーブルを転置して単一の行を取得するスクリプトを作成しました。

次に、作成済みの型を返すFUNCTIONに配置します（selectを実行してから、作成したテーブルからフィールドを取得してカスタム型を作成しました）。これがスクリプトです...実は、pgsqlは関係'q'が存在せず、関数なしでこのSQLの実行が成功したと言っています...シーケンスの作成ができないと推測する必要がありますSQL関数内？ありがとう！！

CREATE OR REPLACE FUNCTION myNewFunction(int) RETURNS SETOF myExistingType AS $$
DROP SEQUENCE IF EXISTS p;
CREATE TEMP sequence p;
DROP SEQUENCE IF EXISTS q;
CREATE TEMP sequence q;
DROP SEQUENCE IF EXISTS r;
CREATE TEMP sequence r;
SELECT
    a.ad_field1,
    a.ad_field2,
    a.ad_field3,
    ...
    a.consecutive
    children.*,
    people.*,
    reffinancieras.*,
    CAST(character varying 'test' as text)
--INTO test_table
FROM 
    pit_adquiriente AS a,

    (SELECT 
        MAX(consulta.n1) as nombrehijo1, 
        MAX(consulta.f1) as fechahijo1, 
        MAX(consulta.n2) as nombrehijo2, 
        MAX(consulta.f2) as fechahijo2,
        MAX(consulta.n3) as nombrehijo3, 
        MAX(consulta.f3) as fechahijo3, 
        MAX(consulta.n4) as nombrehijo4, 
        MAX(consulta.f4) as fechahijo4
    FROM (SELECT adquirientepadre, nextval('q') as consecutivo,
        CASE WHEN currval('q')=1 THEN nombrehijo END as n1,
        CASE WHEN currval('q')=1 THEN fechanacimiento END as f1,
        CASE WHEN currval('q')=2 THEN nombrehijo END as n2 ,
        CASE WHEN currval('q')=2 THEN fechanacimiento END as f2 ,
        CASE WHEN currval('q')=3 THEN nombrehijo END as n3 ,
        CASE WHEN currval('q')=3 THEN fechanacimiento  END as f3,
        CASE WHEN currval('q')=4 THEN nombrehijo END as n4 ,
        CASE WHEN currval('q')=4 THEN fechanacimiento  END as f4 
        FROM pit_adq_hijo
        WHERE adquirientepadre = $1) 
    AS consulta) AS children,

    (SELECT 
        MAX(consulta.nomapeacc1) as nombreapellidoacc1,
        MAX(consulta.identacc1) as idacc1, 
        MAX(consulta.tipoid1) as tipoidacc1,
        MAX(consulta.nomapeacc2) as nombreapellidoacc2,
        MAX(consulta.identacc2) as idacc2, 
        MAX(consulta.tipoid2) as tipoidacc2,
        MAX(consulta.nomapeacc3) as nombreapellidoacc3,
        MAX(consulta.identacc3) as idacc3,
        MAX(consulta.tipoid3) as tipoidacc3,
        MAX(consulta.nomapeacc4) as nombreapellidoacc4,
        MAX(consulta.identacc4) as idacc4,
        MAX(consulta.tipoid4) as tipoidacc4,
        MAX(consulta.nomapeacc5) as nombreapellidoacc5,
        MAX(consulta.identacc5) as idacc5,
        MAX(consulta.tipoid5) as tipoidacc5
    FROM (SELECT codigo_adquiriente, nextval('p') as consecutivo,
        CASE WHEN currval('p')=1 THEN nombre_apellidos END as nomapeacc1,
        CASE WHEN currval('p')=1 THEN identificacion END as identacc1,
        CASE WHEN currval('p')=1 THEN tipo_identificacion END as tipoid1 ,
        CASE WHEN currval('p')=2 THEN nombre_apellidos END as nomapeacc2,
        CASE WHEN currval('p')=2 THEN identificacion END as identacc2,
        CASE WHEN currval('p')=2 THEN tipo_identificacion END as tipoid2 ,
        CASE WHEN currval('p')=3 THEN nombre_apellidos END as nomapeacc3,
        CASE WHEN currval('p')=3 THEN identificacion END as identacc3,
        CASE WHEN currval('p')=3 THEN tipo_identificacion END as tipoid3 ,
        CASE WHEN currval('p')=4 THEN nombre_apellidos END as nomapeacc4,
        CASE WHEN currval('p')=4 THEN identificacion END as identacc4,
        CASE WHEN currval('p')=4 THEN tipo_identificacion END as tipoid4 ,
        CASE WHEN currval('p')=5 THEN nombre_apellidos END as nomapeacc5,
        CASE WHEN currval('p')=5 THEN identificacion END as identacc5,
        CASE WHEN currval('p')=5 THEN tipo_identificacion END as tipoid5 

        FROM pit_people
        WHERE codigo_adquiriente = $1)
    AS consulta) AS people,

    (SELECT 
        MAX(consulta.entfin1) as entidadreff1, 
        MAX(consulta.prod1) as productoreff1, 
        MAX(consulta.num1) as numeroreff1, 
        MAX(consulta.suc1) as sucursalreff1,

        MAX(consulta.entfin2) as entidadreff2, 
        MAX(consulta.prod2) as productoreff2, 
        MAX(consulta.num2) as numeroreff2, 
        MAX(consulta.suc2) as sucursalreff2
    FROM (SELECT codigo_adquiriente, nextval('r') as consecutive,
        CASE WHEN currval('r')=1 THEN entity END as entfin1,
        CASE WHEN currval('r')=1 THEN something END as prod1,
        CASE WHEN currval('r')=1 THEN number_something END as num1 ,
        CASE WHEN currval('r')=1 THEN place_thing END as suc1 ,
        CASE WHEN currval('r')=2 THEN entity END as entfin2,
        CASE WHEN currval('r')=2 THEN something  END as prod2,
        CASE WHEN currval('r')=2 THEN number_something END as num2 ,
        CASE WHEN currval('r')=2 THEN place_thing END as suc2 
        FROM pit_money
        WHERE codigo_adquiriente = $1) 
    AS consulta) AS reffinancieras
WHERE a.consecutive = $1
$$ LANGUAGE SQL;
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1 に答える 1

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通常、このようなことを行うには、配列とgenerate_seriesを使用します。

SELECT CASE WHEN i=1 THEN nombre_apellidos END as nomapeacc1, ...
FROM pit_people p
CROSS JOIN generate_series(1,5) s(i)

しかし、あなたが本当に望んでいるのは、クロス集計を行うことです。 http://www.postgresql.org/docs/8.3/static/tablefunc.html

于 2010-04-23T20:42:00.690 に答える