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I have the following PEGjs productions:

NameStartChar = ":" / [A-Z] / "_" / [a-z] / [\u00C0-\u00D6] / [\u00D8-\u00F6] / [\u00F8-\u02FF] / [\u0370-\u037D] /
                [\u037F-\u1FFF] / [\u200C-\u200D] / [\u2070-\u218F] / [\u2C00-\u2FEF] / [\u3001-\uD7FF] /
                [\uF900-\uFDCF] / [\uFDF0-\uFFFD] / [\uD800-\uDB7F][\uDC00-\uDFFF]

NameChar = NameStartChar / "-" / "." / [0-9] / "\u00B7" / [\u0300-\u036F] / [\u203F-\u2040]

Name = NameStartChar NameChar*

I'd like to somehow get true if my input string matches Name, and false otherwise. I also don't care about parsing out the component parts.

However, PEGjs really wants to throw an exception if the match fails.

I could of course wrap it in a try/catch, but I'd prefer to avoid that. And I'd like to avoid collecting the parsed components as well (i.e., I don't need ["a", ["b", "c", "d"]] when matching "abcd", I just need true).

Is there some hidden PEGjs feature that will make this work? Maybe a clever action, or an innovative use of combinators?

Or perhaps I should be using an entirely different tool, and not a parser-generator? If so, does anyone know what I should be using?

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3 に答える 3

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Name { return true } / { return false }ルールが一致した場合に true を返す式を取得するために使用できます。次に、ケース!.の入力の最後にいることを確認するために追加しtrue、false ケースで最後までスキップするために .* を追加できます。したがって、次のようになります。

ValidateName = Name !. { return true } / .* { return false }
于 2014-12-29T20:35:20.670 に答える
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ValidateName = Name { return true } / { return false }

サブ式でパーサーの位置を進めずに入力を検証する場合は、 を使用できます&Name。

于 2014-12-28T20:48:04.683 に答える