0

私はこのようなテーブルを持っています（最初の列にはIDが含まれ、2番目の列は文字列（いくつかの式）を含むvarcharです）-

column_id       column_formula
4686         4686 = 4684 - 4685 
4687         4687 = ( 4681 / 1.205 / 4684 * 1000 ) 
4717         4717 = ( 4711 + 4712 + 4713 + 4714 + 4715 + 4716 )/6 
4719         4719 = abs( 4716 - 4715 ) 
4787         4787 = max(max(max(max(max( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 ) - min(min(min(min(min( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 )

次のような出力を与えるクエリが必要です-

col1    col2
4686    4684      
4686    4685      
4687    4681 
4687    4684 
4717    4711
4717    4712

など.. (1.205 などの 4 桁未満の数字と 1000 以外の数字のみ)

これでpatindexを使用するのは非常に困難です

これに関する解決策を教えてください

4

2 に答える 2

1

これは、ユーザー定義関数のないソリューションです。はるかに高速になるはずです：

DECLARE @t TABLE ( ID INT, F NVARCHAR(MAX) )

INSERT  INTO @t
VALUES  ( 4686, '4686 = 4684 - 4685' ),
        ( 4687, '4687 = ( 4681 / 1.205 / 4684 * 1000 )' ),
        ( 4717, '4717 = ( 4711 + 4712 + 4713 + 4714 + 4715 + 4716 )/6' ),
        ( 4719, '4719 = abs( 4716 - 4715 ) ' ),
        ( 4787,
          '4787 = max(max(max(max(max( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 ) - min(min(min(min(min( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 )' )

DECLARE @chars TABLE ( ID INT, c NVARCHAR(MAX) )
INSERT  INTO @chars
VALUES  ( 1, ' ' ),
        ( 2, '(' ),
        ( 3, ')' ),
        ( 4, '/' ),
        ( 5, '*' ),
        ( 6, '+' ),
        ( 7, '-' ),
        ( 8, 'max' ),
        ( 9, 'min' ),
        ( 10, 'abs' ),
        ( 11, '=' )

DECLARE @count INT
SELECT  @count = COUNT(*) FROM    @chars;

WITH    recursion
          AS ( SELECT   t.ID ,
                        REPLACE(F, ' ', ',') + ',' AS F ,
                        1 AS CharID
               FROM     @t t
               UNION ALL
               SELECT   t.ID ,
                        REPLACE(t.F, c.c, ',') AS F ,
                        t.CharID + 1 AS CharID
               FROM     recursion t
                        JOIN @chars c ON c.ID = t.CharID + 1
               WHERE    t.CharID < @count
             ),
        commastrings
          AS ( SELECT   ID ,
                        STUFF(F, LEN(F), 1, '') AS F
               FROM     ( SELECT    ID ,
                                    REPLACE(REPLACE(REPLACE(F, ',', '{}'), '}{', ''), '{}', ',') AS F
                          FROM      recursion
                          WHERE     CharID = @count
                        ) a
             ),
        final ( ID, Number, rght, idx )
          AS ( SELECT   t.ID ,
                        LEFT(t.F, CHARINDEX(',', t.F) - 1) ,
                        SUBSTRING(t.F, CHARINDEX(',', t.F) + 1, LEN(t.F)) ,
                        0
               FROM     commastrings t
               UNION ALL
               SELECT   c.id ,
                        CASE WHEN CHARINDEX(',', c.rght) = 0 THEN c.rght
                             ELSE LEFT(c.rght, CHARINDEX(',', c.rght) - 1)
                        END ,
                        CASE WHEN CHARINDEX(',', c.rght) > 0
                             THEN SUBSTRING(c.rght, CHARINDEX(',', c.rght) + 1, DATALENGTH(c.rght))
                             ELSE ''
                        END ,
                        idx + 1
               FROM     final c
               WHERE   LENGTH(c.rght) > 0
             )
    SELECT DISTINCT
            ID ,
            Number
    FROM    final
    WHERE   idx <> 0
            AND CAST(Number AS DECIMAL(20, 10)) > 1000
于 2015-03-12T11:50:59.613 に答える