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ホテルの予約を管理するアプリケーションを作成しており、1 年間の月ごとの稼働率を表示する必要があります。問題を少し解決するクエリを作成しましたが、別の形式で表示したいです。

私の現在のクエリは、次のテーブルを返します (2x12):

January|February|March|April| ..... and so on
   20      15     18     20   ..... and so on

そして、私はこのようなものが欲しい(12x2):

January|20
February|15
March|18
... |...

これは私のクエリです：

Select  
        SUM(CASE WHEN datename(month, [CheckIn]) = 'January' or datename(month, [CheckOut]) = 'January' THEN 1 ELSE 0 END) January,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'February' or datename(month, [CheckOut]) = 'February' THEN 1 ELSE 0 END) February,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'March' or datename(month, [CheckOut]) = 'March' THEN 1 ELSE 0 END) March,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'April' or datename(month, [CheckOut]) = 'April' THEN 1 ELSE 0 END)  April,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'May' or datename(month, [CheckOut]) = 'May' THEN 1 ELSE 0 END)  May,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'June' or datename(month, [CheckOut]) = 'June' THEN 1 ELSE 0 END) June,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'July' or datename(month, [CheckOut]) = 'July' THEN 1 ELSE 0 END) July,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'August' or datename(month, [CheckOut]) = 'August' THEN 1 ELSE 0 END) August,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'September' or datename(month, [CheckOut]) = 'September' THEN 1 ELSE 0 END) September,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'October' or datename(month, [CheckOut]) = 'October' THEN 1 ELSE 0 END) October,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'November' or datename(month, [CheckOut]) = 'November' THEN 1 ELSE 0 END) November,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'December' or datename(month, [CheckOut]) = 'December' THEN 1 ELSE 0 END) December
FROM {Booking} INNER JOIN {Status} ON {Booking}.[StatusId] = {Status}.[Id]
WHERE {Booking}.[CheckIn] >= @BeginDate AND {Booking}.[CheckOut]  <= @EndDate AND {Status}.[Label] <> 'Canceled'

何か助けていただければ幸いです。私は立ち往生しており、ウェブ上にはそれほど多くの情報がありません。ありがとう!

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2 に答える 2

4

あなたがやろうとしているように見えますUNPIVOT:

SELECT Month, CheckIns
FROM
  (Select  
        SUM(CASE WHEN datename(month, [CheckIn]) = 'January' or datename(month, [CheckOut]) = 'January' THEN 1 ELSE 0 END) January,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'February' or datename(month, [CheckOut]) = 'February' THEN 1 ELSE 0 END) February,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'March' or datename(month, [CheckOut]) = 'March' THEN 1 ELSE 0 END) March,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'April' or datename(month, [CheckOut]) = 'April' THEN 1 ELSE 0 END)  April,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'May' or datename(month, [CheckOut]) = 'May' THEN 1 ELSE 0 END)  May,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'June' or datename(month, [CheckOut]) = 'June' THEN 1 ELSE 0 END) June,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'July' or datename(month, [CheckOut]) = 'July' THEN 1 ELSE 0 END) July,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'August' or datename(month, [CheckOut]) = 'August' THEN 1 ELSE 0 END) August,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'September' or datename(month, [CheckOut]) = 'September' THEN 1 ELSE 0 END) September,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'October' or datename(month, [CheckOut]) = 'October' THEN 1 ELSE 0 END) October,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'November' or datename(month, [CheckOut]) = 'November' THEN 1 ELSE 0 END) November,
        SUM(CASE WHEN datename(month, [CheckIn]) = 'December' or datename(month, [CheckOut]) = 'December' THEN 1 ELSE 0 END) December
  FROM {Booking} INNER JOIN {Status} ON {Booking}.[StatusId] = {Status}.[Id]
  WHERE {Booking}.[CheckIn] >= @BeginDate AND {Booking}.[CheckOut]  <= @EndDate AND {Status}.[Label] <> 'Canceled'
) monthTotals
UNPIVOT
(CheckIns FOR Month IN
   (January, February, March, April, May, June, July, August, September, October, November, December)
) AS upvt

これは、これの単純化された SQLFiddle です。

そして、ここにドキュメントページがPIVOTありますUNPIVOT

于 2015-03-13T15:58:34.847 に答える
1

ケースステートメントを少し短く/単純にして、読みやすくすることができます。MONTH() は読みやすい関数であり、else を取り除くことは、単純に SUM() が 0 のように扱う null を返すことを意味します。

SELECT [Month], CheckIns
FROM
  (
  Select  
        SUM(CASE WHEN MONTH([CheckIn]) = 01 or MONTH([CheckOut]) = 01 THEN 1 END) January,
        SUM(CASE WHEN MONTH([CheckIn]) = 02 or MONTH([CheckOut]) = 02 THEN 1 END) February,
        SUM(CASE WHEN MONTH([CheckIn]) = 03 or MONTH([CheckOut]) = 03 THEN 1 END) March,
        SUM(CASE WHEN MONTH([CheckIn]) = 04 or MONTH([CheckOut]) = 04 THEN 1 END) April,
        SUM(CASE WHEN MONTH([CheckIn]) = 05 or MONTH([CheckOut]) = 05 THEN 1 END) May,
        SUM(CASE WHEN MONTH([CheckIn]) = 06 or MONTH([CheckOut]) = 06 THEN 1 END) June,
        SUM(CASE WHEN MONTH([CheckIn]) = 07 or MONTH([CheckOut]) = 07 THEN 1 END) July,
        SUM(CASE WHEN MONTH([CheckIn]) = 08 or MONTH([CheckOut]) = 08 THEN 1 END) August,
        SUM(CASE WHEN MONTH([CheckIn]) = 09 or MONTH([CheckOut]) = 09 THEN 1 END) September,
        SUM(CASE WHEN MONTH([CheckIn]) = 10 or MONTH([CheckOut]) = 10 THEN 1 END) October,
        SUM(CASE WHEN MONTH([CheckIn]) = 11 or MONTH([CheckOut]) = 11 THEN 1 END) November,
        SUM(CASE WHEN MONTH([CheckIn]) = 12 or MONTH([CheckOut]) = 12 THEN 1 END) December
  FROM [Booking] 

  INNER JOIN {Status} ON {Booking}.[StatusId] = {Status}.[Id]
  WHERE {Booking}.[CheckIn] >= @BeginDate AND {Booking}.[CheckOut]  <= @EndDate AND {Status}.[Label] <> 'Canceled'
) MONTHTotals
UNPIVOT
(
CheckIns FOR [Month] IN
   (January, February, March, April, May, June, July, August, September, October, November, December)
) AS upvt
于 2015-03-13T17:04:56.093 に答える