bison - エラーをシフト/削減 BISON

Question

文法をコンパイルしようとすると、2 つの shift/reduce エラーが発生します。

program : declaration_list ;
declaration_list : declaration_list declaration | declaration ;
declaration : var_declaration | fun_declaration ; 

var_declaration: type_specifier var_decl_list ;
scoped_var_declaration: scoped_type_specifier var_decl_list;
var_decl_list : var_decl_list "," var_decl_initialize | var_decl_initialize ;
var_decl_initialize : var_decl_id ;
var_decl_id : ID | ID "[" INT_NUM "]" ;
scoped_type_specifier : type_specifier;
type_specifier: INT | CHAR ;
fun_declaration: type_specifier ID "(" params ")" statement | ID "(" params ")" statement ;
params : | param_list ;
param_list: param_list ";" param_type_list | param_type_list ;
param_type_list : type_specifier param_id_list ; 
param_id_list : param_id_list "," param_id | param_id ; 
param_id : ID | ID "[" "]" ;


statement: expression_stmt | compound_stmt | selection_stmt | iteration_stmt | return_stmt | break_stmt ;

compound_stmt : "{" local_declaration statement_list "}" ;
local_declaration : | local_declaration scoped_var_declaration ;
statement_list : | statement_list statement ;
expression_stmt : expression ";" | ";" ;
selection_stmt : "if" "(" simple_expression ")" statement | "if" "(" simple_expression ")" statement "else" statement ;
iteration_stmt: "while" "(" simple_expression ")" statement ;
return_stmt : "return" ";" | "return" expression ;
break_stmt : "break" ;


expression : mutable ASSIGN expression | mutable EINC expression | mutable EDEC expression | mutable INC | mutable DEC | simple_expression ;

simple_expression: simple_expression OR and_expression | and_expression ; 

and_expression: and_expression AND unary_rel_expression | unary_rel_expression ;

unary_rel_expression: "!" unary_rel_expression | rel_expression ;

rel_expression : sum_expression relop sum_expression | sum_expression ;

relop: "<" | ">" | LE | GE | COMP_OP | NE ;

sum_expression : sum_expression sumop term | term ; 

sumop : ADD | SUB ;

term: term mulop unary_expression | unary_expression ;

mulop: MULT | DIV | REM ;

unary_expression : unaryop unary_expression | factor ;

unaryop : "-" | "*" ;

factor : immutable | mutable ;

mutable : ID | ID "[" expression "]" ;

immutable : "(" expression ")" | call | constant ; 

call: ID "(" args ")" ;

args:  | arg_list;

arg_list : arg_list","expression | expression ;

constant : INT_NUM | STRINGCONST | CHARCONST | 'true' | 'false' ;

私は2シフト/削減を取得します

状態 38 の競合: 1 シフト/削減 状態 139 の競合: 1 シフト/削減

特定の状態は次のとおりです。

state 38

   81 mutable: ID .  [$end, ADD, SUB, DIV, MULT, COMP_OP, INT, CHAR, CHARCONST, STRINGCONST, GE, LE, NE, EINC, EDEC, INC, DEC, AND, OR, REM, ASSIGN, INT_NUM, ID, ",", "]", "(", ")", ";", "{", "}", "if", "else", "while", "return", "break", "!", "<", ">", "-", "*", 't', 'f']
   82        | ID . "[" expression "]"
   86 call: ID . "(" args ")"

    "["  shift, and go to state 77
    "("  shift, and go to state 78

    "("       [reduce using rule 81 (mutable)]
    $default  reduce using rule 81 (mutable)




state 139

   40 selection_stmt: "if" "(" simple_expression ")" statement .  [$end, INT, CHAR, CHARCONST, STRINGCONST, INT_NUM, ID, "(", ";", "{", "}", "if", "else", "while", "return", "break", "!", "-", "*", 't', 'f']
   41               | "if" "(" simple_expression ")" statement . "else" statement

    "else"  shift, and go to state 141

    "else"    [reduce using rule 40 (selection_stmt)]
    $default  reduce using rule 40 (selection_stmt)

誰かがこのエラーを修正する方法を説明してもらえますか?私はそれが優先順位と関係があることを知っています.