私は検索バーを理解しようとしています.APIを持っています.APIを「どこに」送信すると、データが得られます. しかし、リターンキーをタップしても何も得られません。
私のコードがあります。
- (void)searchBarSearchButtonClicked:(UISearchBar *)searchBar
{
AFSecurityPolicy *securityPolicy = [[AFSecurityPolicy alloc] init];
[securityPolicy setAllowInvalidCertificates:YES];
NSString *urlPath = [NSString stringWithFormat:@"http://test.com/api/index.php"];
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
NSDictionary *parameters = @{@"process":@"search_record",@"where": self.searchBar.text};
manager.responseSerializer.acceptableContentTypes = [NSSet setWithObject:@"text/html"];
[manager setSecurityPolicy:securityPolicy];
manager.responseSerializer = [AFHTTPResponseSerializer serializer];
[manager POST:urlPath parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSString *string = [[NSString alloc] initWithData:responseObject encoding:NSUTF8StringEncoding];
NSError *error = nil;
NSData *jsonData = [string dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *dataDictionary = [NSJSONSerialization JSONObjectWithData:jsonData options:0 error:&error];
self.customerCards = [NSMutableArray array];
NSArray *customersArray = [dataDictionary objectForKey:@"customer_list"];
NSLog(@"%@",customersArray);
for (NSDictionary *customersDictionary in customersArray) {
ApiClass *customer = [ApiClass customersWithTitle:[customersDictionary objectForKey:@"adi"]];
customer.tel = [customersDictionary objectForKey:@"tel"];
[self.customerCards addObject:customer];
}
[self.tableView reloadData];
NSLog(@"GET: %@", string);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
}
私は何をすべきか。
ありがとう