PHP、JavaScript、その他多くのスクリプト言語の経験がありますが、Java や Android の経験はあまりありません。
POSTデータを PHP スクリプト に送信し、結果を表示する方法を探しています。
526058 次
16 に答える
329
注 (2020 年 10 月): 次の回答で使用されている AsyncTask は、Android API レベル 30 で廃止されました。より更新された例については、公式ドキュメントまたはこのブログ投稿を参照してください。
更新 (2017 年 6 月) Android 6.0 以降で動作する回答。@Rohit Suthar、@Tamis Bolvari、 @ sudhiskrのコメントに感謝します。
public class CallAPI extends AsyncTask<String, String, String> {
public CallAPI(){
//set context variables if required
}
@Override
protected void onPreExecute() {
super.onPreExecute();
}
@Override
protected String doInBackground(String... params) {
String urlString = params[0]; // URL to call
String data = params[1]; //data to post
OutputStream out = null;
try {
URL url = new URL(urlString);
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
out = new BufferedOutputStream(urlConnection.getOutputStream());
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
writer.write(data);
writer.flush();
writer.close();
out.close();
urlConnection.connect();
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
}
参考文献:
- https://developer.android.com/reference/java/net/HttpURLConnection.html
- NameValuePair を使用して POST を使用して HttpURLConnection にパラメーターを追加する方法
元の回答 (2010 年 5 月)
注: このソリューションは古くなっています。5.1 までの Android デバイスでのみ動作します。Android 6.0 以降には、この回答で使用されている Apache http クライアントは含まれていません。
Apache Commons の Http Client が最適です。アンドロイドにはすでに搭載されています。これを使用して HTTP Post を実行する方法の簡単な例を次に示します。
public void postData() {
// Create a new HttpClient and Post Header
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.yoursite.com/script.php");
try {
// Add your data
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("id", "12345"));
nameValuePairs.add(new BasicNameValuePair("stringdata", "Hi"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
HttpResponse response = httpclient.execute(httppost);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
} catch (IOException e) {
// TODO Auto-generated catch block
}
}
于 2010-05-30T13:24:09.513 に答える
99
Androidの場合= > 5
org.apache.httpクラスとAndroidHttpClientクラスはAndroid 5.1で廃止されました。これらのクラスはメンテナンスされなくなりました。これらの API を使用するアプリ コードは、できるだけ早くURLConnectionクラスに移行する必要があります。
https://developer.android.com/about/versions/android-5.1.html#http
HttpUrlConnectionを使用してコードを共有することを考えました
public String performPostCall(String requestURL,
HashMap<String, String> postDataParams) {
URL url;
String response = "";
try {
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("GET");
conn.setDoInput(true);
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(getPostDataString(postDataParams));
writer.flush();
writer.close();
os.close();
int responseCode=conn.getResponseCode();
if (responseCode == HttpsURLConnection.HTTP_OK) {
String line;
BufferedReader br=new BufferedReader(new InputStreamReader(conn.getInputStream()));
while ((line=br.readLine()) != null) {
response+=line;
}
}
else {
response="";
}
} catch (Exception e) {
e.printStackTrace();
}
return response;
}
...
private String getPostDataString(HashMap<String, String> params) throws UnsupportedEncodingException{
StringBuilder result = new StringBuilder();
boolean first = true;
for(Map.Entry<String, String> entry : params.entrySet()){
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
result.append("=");
result.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
}
return result.toString();
}
また、メソッドを投稿することもできます：
conn.setRequestMethod("POST");
2016 年 2 月 21 日更新
jsonを使用したポストリクエストについては、次の例を参照してください。
public class Empty extends
AsyncTask<Void, Void, Boolean> {
String urlString = "http://www.yoursite.com/";
private final String TAG = "post json example";
private Context context;
private int advertisementId;
public Empty(Context contex, int advertisementId) {
this.context = contex;
this.advertisementId = advertisementId;
}
@Override
protected void onPreExecute() {
Log.e(TAG, "1 - RequestVoteTask is about to start...");
}
@Override
protected Boolean doInBackground(Void... params) {
boolean status = false;
String response = "";
Log.e(TAG, "2 - pre Request to response...");
try {
response = performPostCall(urlString, new HashMap<String, String>() {
private static final long serialVersionUID = 1L;
{
put("Accept", "application/json");
put("Content-Type", "application/json");
}
});
Log.e(TAG, "3 - give Response...");
Log.e(TAG, "4 " + response.toString());
} catch (Exception e) {
// displayLoding(false);
Log.e(TAG, "Error ...");
}
Log.e(TAG, "5 - after Response...");
if (!response.equalsIgnoreCase("")) {
try {
Log.e(TAG, "6 - response !empty...");
//
JSONObject jRoot = new JSONObject(response);
JSONObject d = jRoot.getJSONObject("d");
int ResultType = d.getInt("ResultType");
Log.e("ResultType", ResultType + "");
if (ResultType == 1) {
status = true;
}
} catch (JSONException e) {
// displayLoding(false);
// e.printStackTrace();
Log.e(TAG, "Error " + e.getMessage());
} finally {
}
} else {
Log.e(TAG, "6 - response is empty...");
status = false;
}
return status;
}
@Override
protected void onPostExecute(Boolean result) {
//
Log.e(TAG, "7 - onPostExecute ...");
if (result) {
Log.e(TAG, "8 - Update UI ...");
// setUpdateUI(adv);
} else {
Log.e(TAG, "8 - Finish ...");
// displayLoding(false);
// finish();
}
}
public String performPostCall(String requestURL,
HashMap<String, String> postDataParams) {
URL url;
String response = "";
try {
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(context.getResources().getInteger(
R.integer.maximum_timeout_to_server));
conn.setConnectTimeout(context.getResources().getInteger(
R.integer.maximum_timeout_to_server));
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setRequestProperty("Content-Type", "application/json");
Log.e(TAG, "11 - url : " + requestURL);
/*
* JSON
*/
JSONObject root = new JSONObject();
//
String token = Static.getPrefsToken(context);
root.put("securityInfo", Static.getSecurityInfo(context));
root.put("advertisementId", advertisementId);
Log.e(TAG, "12 - root : " + root.toString());
String str = root.toString();
byte[] outputBytes = str.getBytes("UTF-8");
OutputStream os = conn.getOutputStream();
os.write(outputBytes);
int responseCode = conn.getResponseCode();
Log.e(TAG, "13 - responseCode : " + responseCode);
if (responseCode == HttpsURLConnection.HTTP_OK) {
Log.e(TAG, "14 - HTTP_OK");
String line;
BufferedReader br = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
while ((line = br.readLine()) != null) {
response += line;
}
} else {
Log.e(TAG, "14 - False - HTTP_OK");
response = "";
}
} catch (Exception e) {
e.printStackTrace();
}
return response;
}
}
2016 年 8 月 24 日更新
次のような最適なライブラリを使用します。
なぜなら ：
- HttpUrlConnection と HttpClient を避ける
下位の API レベル (主に Gingerbread と Froyo) では、HttpUrlConnection と HttpClient は完璧とは言えません。
- AsyncTask も避ける
- 彼らははるかに高速です
- 彼らはすべてをキャッシュします
Honeycomb (API 11) の導入以来、メイン スレッドとは異なる別のスレッドでネットワーク操作を実行することが必須になっています。
于 2015-07-11T12:44:40.957 に答える
50
このようにして、http post メソッドでデータを送信し、結果を取得できます
public class MyHttpPostProjectActivity extends Activity implements OnClickListener {
private EditText usernameEditText;
private EditText passwordEditText;
private Button sendPostReqButton;
private Button clearButton;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
usernameEditText = (EditText) findViewById(R.id.login_username_editText);
passwordEditText = (EditText) findViewById(R.id.login_password_editText);
sendPostReqButton = (Button) findViewById(R.id.login_sendPostReq_button);
sendPostReqButton.setOnClickListener(this);
clearButton = (Button) findViewById(R.id.login_clear_button);
clearButton.setOnClickListener(this);
}
@Override
public void onClick(View v) {
if(v.getId() == R.id.login_clear_button){
usernameEditText.setText("");
passwordEditText.setText("");
passwordEditText.setCursorVisible(false);
passwordEditText.setFocusable(false);
usernameEditText.setCursorVisible(true);
passwordEditText.setFocusable(true);
}else if(v.getId() == R.id.login_sendPostReq_button){
String givenUsername = usernameEditText.getEditableText().toString();
String givenPassword = passwordEditText.getEditableText().toString();
System.out.println("Given username :" + givenUsername + " Given password :" + givenPassword);
sendPostRequest(givenUsername, givenPassword);
}
}
private void sendPostRequest(String givenUsername, String givenPassword) {
class SendPostReqAsyncTask extends AsyncTask<String, Void, String>{
@Override
protected String doInBackground(String... params) {
String paramUsername = params[0];
String paramPassword = params[1];
System.out.println("*** doInBackground ** paramUsername " + paramUsername + " paramPassword :" + paramPassword);
HttpClient httpClient = new DefaultHttpClient();
// In a POST request, we don't pass the values in the URL.
//Therefore we use only the web page URL as the parameter of the HttpPost argument
HttpPost httpPost = new HttpPost("http://www.nirmana.lk/hec/android/postLogin.php");
// Because we are not passing values over the URL, we should have a mechanism to pass the values that can be
//uniquely separate by the other end.
//To achieve that we use BasicNameValuePair
//Things we need to pass with the POST request
BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("paramUsername", paramUsername);
BasicNameValuePair passwordBasicNameValuePAir = new BasicNameValuePair("paramPassword", paramPassword);
// We add the content that we want to pass with the POST request to as name-value pairs
//Now we put those sending details to an ArrayList with type safe of NameValuePair
List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
nameValuePairList.add(usernameBasicNameValuePair);
nameValuePairList.add(passwordBasicNameValuePAir);
try {
// UrlEncodedFormEntity is an entity composed of a list of url-encoded pairs.
//This is typically useful while sending an HTTP POST request.
UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList);
// setEntity() hands the entity (here it is urlEncodedFormEntity) to the request.
httpPost.setEntity(urlEncodedFormEntity);
try {
// HttpResponse is an interface just like HttpPost.
//Therefore we can't initialize them
HttpResponse httpResponse = httpClient.execute(httpPost);
// According to the JAVA API, InputStream constructor do nothing.
//So we can't initialize InputStream although it is not an interface
InputStream inputStream = httpResponse.getEntity().getContent();
InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
StringBuilder stringBuilder = new StringBuilder();
String bufferedStrChunk = null;
while((bufferedStrChunk = bufferedReader.readLine()) != null){
stringBuilder.append(bufferedStrChunk);
}
return stringBuilder.toString();
} catch (ClientProtocolException cpe) {
System.out.println("First Exception caz of HttpResponese :" + cpe);
cpe.printStackTrace();
} catch (IOException ioe) {
System.out.println("Second Exception caz of HttpResponse :" + ioe);
ioe.printStackTrace();
}
} catch (UnsupportedEncodingException uee) {
System.out.println("An Exception given because of UrlEncodedFormEntity argument :" + uee);
uee.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if(result.equals("working")){
Toast.makeText(getApplicationContext(), "HTTP POST is working...", Toast.LENGTH_LONG).show();
}else{
Toast.makeText(getApplicationContext(), "Invalid POST req...", Toast.LENGTH_LONG).show();
}
}
}
SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
sendPostReqAsyncTask.execute(givenUsername, givenPassword);
}
}
于 2012-09-12T07:11:12.000 に答える
24
これは、外部 Apache ライブラリを使用せずにマルチパート データを POST する方法の例です。
byte[] buffer = getBuffer();
if(buffer.length > 0) {
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "RQdzAAihJq7Xp1kjraqf";
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
// Send parameter #1
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param1\"" + lineEnd);
dos.writeBytes("Content-Type: text/plain; charset=US-ASCII" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: 8bit" + lineEnd);
dos.writeBytes(lineEnd);
dos.writeBytes(myStringData + lineEnd);
// Send parameter #2
//dos.writeBytes(twoHyphens + boundary + lineEnd);
//dos.writeBytes("Content-Disposition: form-data; name=\"param2\"" + lineEnd + lineEnd);
//dos.writeBytes("foo2" + lineEnd);
// Send a binary file
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"param3\";filename=\"test_file.dat\"" + lineEnd);
dos.writeBytes("Content-Type: application/octet-stream" + lineEnd);
dos.writeBytes("Content-Transfer-Encoding: binary" + lineEnd);
dos.writeBytes(lineEnd);
dos.write(buffer);
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
dos.flush();
dos.close();
ByteArrayInputStream content = new ByteArrayInputStream(baos.toByteArray());
BasicHttpEntity entity = new BasicHttpEntity();
entity.setContent(content);
HttpPost httpPost = new HttpPost(myURL);
httpPost.addHeader("Connection", "Keep-Alive");
httpPost.addHeader("Content-Type", "multipart/form-data; boundary="+boundary);
//MultipartEntity entity = new MultipartEntity();
//entity.addPart("param3", new ByteArrayBody(buffer, "test_file.dat"));
//entity.addPart("param1", new StringBody(myStringData));
httpPost.setEntity(entity);
/*
String httpData = "";
ByteArrayOutputStream baos1 = new ByteArrayOutputStream();
entity.writeTo(baos1);
httpData = baos1.toString("UTF-8");
*/
/*
Header[] hdrs = httpPost.getAllHeaders();
for(Header hdr: hdrs) {
httpData += hdr.getName() + " | " + hdr.getValue() + " |_| ";
}
*/
//Log.e(TAG, "httpPost data: " + httpData);
response = httpClient.execute(httpPost);
}
于 2012-06-28T07:57:58.320 に答える
8
以下を使用して、にHTTP-POSTリクエストを送信しURL、レスポンスを受信できます。私はいつもこれを使用します：
try {
AsyncHttpClient client = new AsyncHttpClient();
// Http Request Params Object
RequestParams params = new RequestParams();
String u = "B2mGaME";
String au = "gamewrapperB2M";
// String mob = "880xxxxxxxxxx";
params.put("usr", u.toString());
params.put("aut", au.toString());
params.put("uph", MobileNo.toString());
// params.put("uph", mob.toString());
client.post("http://196.6.13.01:88/ws/game_wrapper_reg_check.php", params, new AsyncHttpResponseHandler() {
@Override
public void onSuccess(String response) {
playStatus = response;
//////Get your Response/////
Log.i(getClass().getSimpleName(), "Response SP Status. " + playStatus);
}
@Override
public void onFailure(Throwable throwable) {
super.onFailure(throwable);
}
});
} catch (Exception e) {
e.printStackTrace();
}
libsフォルダーに次のJarファイルを追加する必要もあります
android-async-http-1.3.1.jar
最後に、build.gradle を編集しました。
dependencies {
compile files('libs/<android-async-http-1.3.1.jar>')
}
最後に プロジェクトを再構築します。
于 2015-07-09T08:22:32.333 に答える
7
Androidにも既に含まれているApache Commons HttpClientを使用することをお勧めします。 一般的な API 情報については、 Android Developer: Apache HTTP Client Package Summaryをご覧ください。
于 2010-05-30T13:14:45.117 に答える
6
For me works next :
private sendData() {
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("key1", value1);
jsonObject.accumulate("key2", value2);
boolean success = sendPost(SERVER_URL + "/v1/auth", jsonObject);
}
private boolean sendPost(String url, JSONObject parameters) {
boolean requestResult = false;
InputStream inputStream = null;
String result = "";
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
String json = "";
json = parameters.toString();
StringEntity se = new StringEntity(json);
httpPost.setEntity(se);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
HttpResponse httpResponse = httpclient.execute(httpPost);
inputStream = httpResponse.getEntity().getContent();
if (inputStream != null) {
result = convertInputStreamToString(inputStream);
requestResult = true;
} else {
result = "Did not work!";
requestResult = false;
}
System.out.println(result);
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
requestResult = false;
}
return requestResult;
}
于 2015-10-15T11:01:27.860 に答える
6
、(データの送信用)、およびURLConnection(受信用)と共に使用できます。Sun には、まさにこの例があります。setDoOutput(true)getOutputStream() getInputStream()
于 2010-05-30T12:01:34.613 に答える
3
データをHTTPリクエストとして投稿する方法、
public static InputStream callPostService(String Url,
List<NameValuePair> data) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(Url);
try {
httppost.setEntity(new UrlEncodedFormEntity(data));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
return entity.getContent();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
于 2013-06-27T11:01:35.693 に答える
1
Android の新しいバージョンでは、すべての Web I/O リクエストを新しいスレッドに入れる必要があります。AsyncTask は小さなリクエストに最適です。
于 2013-07-15T22:16:00.303 に答える
0
The below method works with latest Android Libraries and using okhttp.
OkHttpClient client = new OkHttpClient();
RequestBody formBody = new FormBody.Builder()
.add("key1", "value1")
.add("key2", "value2") //optional
.add("key3", "value3") //optional
.add("key4", "value4") //optional
.build();
Request request = new Request.Builder()
.url("http://.....") //URL
.post(formBody)
.build();
client.newCall(request).enqueue(new Callback() {
@Override
public void onFailure(@NonNull Call call, @NonNull IOException e) {
e.getStackTrace();
}
@Override
public void onResponse(@NonNull Call call, @NonNull Response response) throws IOException {
if(response.isSuccessful()){
ResponseBody responseBody = response.body();
Log.e("TAG_", responseBody.string());
}
}
于 2021-10-24T21:14:49.703 に答える